1. Galactosemia is a disease that will only be expressed when a person is<span><span><span> homozygotic recessive for that trait. It's the same as saying it </span> has</span> 2 recessive alleles.
Dominant allele-</span><span> G
recessive allele- g
</span>
Homozygotic dominant: GG <span><span>(doesn't express the disease)
</span>Heterozygotic : Gg (doesn't express the disease)
Homozygotic recessive: gg (expresses it)</span>
2.
-Mary has this genotype: G_ . This means it can be GG or Gg
-The exercise already says that justin's mother is GG (<span>Homozygotic dominant)
</span>- If his mother is GG, one of these G's is going to be passed to Justin. So, his genotype is either GG or Gg. Since we are not sure we write as: G_.
Justin's genotype: G_
3.
-Justin's uncle has galactosemia so his genotype is: gg
-If the uncle was able to receive two recessive alleles it means the mother had one to pass, and so did the father. However, in the diagram, it's not pointed out that they have a disease so it only leaves one possible genotype: Gg. Justin's grandparents are both Gg.
4. The last person to analyze is Justin's father.
If we crossed the grandparents (Gg x Gg) we could obtain these genotypes: GG, Gg, gg.
Justin's father doesn't express the trait, so it's not gg. That leaves us with either GG or Gg. Since we can't know for sure, onece again we write as G_
Justin's father: G_
Through the process of Meiosis
Answer:
Beak shape/size or song or behavior or mechanical/chemical differences or time of mating or location on the island or primary food source differs between the Big Bird lineage and G. fortis.
Also acceptable: Description of another mechanism that prevents males and females from different populations from encountering each other/recognizing each other as potential mates.
Answer:
C) It can show you which organism is most closely related to the human.
Explanation:
Different proteins might have same structure and function in different organisms
Identifying the genetic sex of a child is based on finding intracellular Barr bodies that consist of inactive chromatin material.
Inactive chromatin material is the one where no transcription takes place. It is also known by the name heterochromatin. It appears as a dark condensed form in the chromatin.
Barr bodies are the inactive X chromosomes. These are mad inactive by a process termed as lyonization. It is essential to make the chromosome inactive in organisms with XY type of sex determination. They are present at the periphery of the nucleus. Inactivation of X chromosome makes the amount of X chromosomes equal in both, males and females.
To know more about Barr bodies, here
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