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3 years ago

Please solve this for me 9x+6+45=100

Mathematics

2 answers:

ss7ja [257]3 years ago

8 0

Answer:

9x+6+45=100

Transposing (45) to RHS

= 9x+6=100-45

= 9x6=55

Now, transposing (6) to RHS

= 9x=55-6

= 9x=49

Now, transposing (9) to RHS

= x=49÷9

= x=5.44.....

Therefore, value of x=5.44..............

mamaluj [8]3 years ago

5 0

I hope this helps with your answer

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The area of a trapezoid is 70.55 square feet. The length of the bases are 11.4 and 5.6 feet. What is the height of the trapezoid

olasank [31]

Answer:

The height is 8.3 feet

Step-by-step explanation:

The area of a trapezoid is calculated using the formula:

Area=½(sum of bases)*height

We substitute area=70.55, and the base lengths 11.4 and 5.6 feet and solve for the height.

$70.55 = \frac{1}{2} (11.4 + 5.6)h$

$70.55 = \frac{1}{2} (17)h$

$70 .55 = 8.5h$

$h = \frac{70.55}{8.5}$

$h = 8.3$

5 0

3 years ago

Read 2 more answers

Need this really quick plz

Oduvanchick [21]

Answer:

Let

x=sin-¹u

Sinx=u

let y=tan-¹v

tany=v

Substituting

Sin[x + y]

Applying the sine expansion

Sinxcosy + CosxSiny

Recall x =Sin-¹u

y=tan-¹v

Sin(Sin-¹u)Cos(tan-¹v) +Cos(sin-¹u)Sin(tan-¹v)

Now at this point

Here's what you do

For the first expression

Sin(Sin-¹u)

Let's simplify this

Let P = Sin-¹u

Taking sine of both sides

SinP=u

Draw a Right angled angle for this

Since Sine from SOHCAHTOA is OPP/HYP

Where P is the angle and u is the opposite and 1 is the hypotenuse since u is the same as u/1

substituting Sin-¹u = P

You have

Sin(Sin-¹u) = SinP

and from the triangle you drew

SinP = u

Taking the second express

Cos(tan-¹v)

Let Q=Tan-¹v

taking tan of both sides

tanQ=v

Draw a right angled triangle for this too

Since Tan from SOHCAHTOA is OPP/ADJ

Find the Hypotenuse cos you'll need it

Now Let's do the substitution again

We first said tan-¹v = Q

When we substitute it in Cos(tan-¹v)

We have CosQ

Cos Q from the second right angle triangle you drew is 1/√1+v²

Because CAH is adj/Hyp

the first part of the original Express

Which is

Sin(Sin-¹u)Cos(tan-¹v) is now simplified to

u(1/√1+v²).

Let's Move to the second part of the Original Expression

Cos(Sin-¹u)Sin(tan-¹v)

From our first solution

We said Sin-¹u= P

So replacing it here

we have Cos(sin-¹u) = CosP

let's leave the second one for now which is sin(tan-1v) We'll deal with this after the first

so Cos(Sin-¹u) = CosP

we can still use our first Right angle triangle for this because the angle was P.

so Cos P from that triangle will be

CosP= √1-u²

Now onto the next

Sin(tan-¹v)

From the Second solution of the first we did

we said let Tan-¹v =Q

Substituting this

we have

Sin(tan-¹v) = SinQ

using the second Right angle triangle because its angle is Q

We have

SinQ= v/√1+v²

Answer for second phase Which is

Cos(sin-¹u)Sin(tan-¹v) = √1-u²(v/√1+v²)

We're done

compiling our answers

The answer to

Sin(Sin-¹u - tan-¹v) = u(1/√1+v²) + [(√1-u²)(v/√1+v²)]

You can still choose to factor out 1/√1+v² since it appears on both sides

8 0

3 years ago

Show that (−3) × (−4) = +12 using the distributive property.

Kobotan [32]

-3x-4= +12

X negative 3 and 4 then add +12 to it.

3 0

4 years ago

What is 3/10, -1 1/3, 0.02, 1, -0.5 in order form least to greatest

baherus [9]

Answer:

-1 1/3, -0.5, 0.02, 3/10, 1

Step-by-step explanation:

To start off with, we now that negative numbers (like -3) are less than 0. We are given two negative numbers to start off with: -1 1/3 and -0.5. The larger/greater the negative number is, the lesser it is worth. Take out a number line. For example, -5 is less than -3 because if you look at a number line, -5 is further to the left of 0 than -3, signifying it is less than -3. So, when looking at -1 1/3 (also can be represented by the decimal number (-1.33...) and -0.5 we see that -1 1/3 is less than -0.5. due to it being further from 0 than -0.5 is. Thus, we have our least number.

-1 1/3

Since we have only one more negative number left, we can place that as the second least number

-1 1/3, -0.5

Next, we take a look at the positive numbers 0.02, 1, and 3/10. It might be more helpful to make 0.02 into a fraction; 2/100. From here we see that one one hundredth is much less than one one tenth. Thus, the 2/100 or 0.02 is the nest least number.

-1 1/3, -0.5, 0.02

Lastly, take a look at 3/10 and 1. 1 = 10/10

When put side by side, 3/10 is seen to be less than 10/10, making it the next least number.

-1 1/3, -0.5, 0.02, 3/10

Lastly, we have our last and greatest number; 1. We can just go ahead and place that after 3/10.

-1 1/3, -0.5, 0.02, 3/10, 1

7 0

3 years ago

ABCD is a square with 8-inch sides. Point E is the midpoint of side AB and point F is the midpoint of side BC. What is the area

3241004551 [841]

Answer:

<u>The area of triangle DEF is equal to 8√3</u>

Step-by-step explanation:

Firstly, side DF is the hypothenuse to the formed right triangle ADE. As side AD has a length of 8 and side AE has a length of 4, we can substitute these values into the Pythagorean theorem:

A^2 + B^2 = C^2

8^2 + 4^2 = C^2

64 + 16 = C^2

80 = C^2

√(80) = √(C^2)

4√5 = C

This means that side DE of triangle DEF is equal to a length of 4√5, and the side DF is also equal to this length because of how squares are congruent as shown in the diagram. This means all we have to do is find the length of side EF.

As side EB and BF is equal to 4, we can create the Pythagorean theorem once again:

A^2 + B^2 = C^2

4^2 + 4^2 = C^2

16 + 16 = C^2

32 = C^2

√(32) = √(C^2)

4√2 = C

Now, we have a triangle to work with! This triangle is triangle DEF and now we have to find the area of the newly defined triangle. To do this, we take the formula for the area of a triangle, A = (HB)/(2), and find values to substitute. Because we do not have height for this triangle, we have to use the Pythagorean theorem once again and hopefully for the last time!

We can bisect side EF with a perpendicular bisector to point D. By doing so, we are creating a line that can be used to solve the height of this triangle. We can now use the theorem:

A^2 + B^2 = C^2

A^2 + (2√2)^2 = (4√2)^2

A^2 + 8 = 32

A^2 = 24

√(A^2) = √24

A = 2√6

Finally! We can now substitute known values into the equation A = (HB)/(2).

A = (HB)/(2)

A = [(2√6)(4√2)]/(2)

A = (16√3)/(2)

A = 8√3

<u>This means that the area of triangle DEF is equal to 8√3!</u>

5 0

3 years ago

Read 2 more answers