F(x) = x2+2x-3 = 1
g(x) = x2-9 = -7
(f/g)(4) = (1/-7)(4) = (-0.14)(4) = -0.57
(f+g)(4) = (1+(-7))(4) = (-6)(4) = -24
For solving of the area of a square pyramid, we can use the formula below:
A=a²+2a sqrt (a²/4 +h²)
where s for the slant height, r for the a/2, where a is the side length and h for the height
Substitute the values,
A=40²+(2*40) SQRT (40²/4 +21²)
A=3920
The answer is 3920 for the area of the square pyramid.
Answer:
let number=x
According to given condition
6-x=x-2(5)
6-x=x-10
6+10=x+x
16=2x
16/2=x
8=x
