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tino4ka555 [31]
3 years ago
15

Marvin bought some softballs and hardballs for the high school teams he coaches. Softballs cost $5 each, and hardballs cost $4 e

ach. Marvin can spend no more than $20. If \displaystyle xx represents the number of hardballs be bought, and \displaystyle yy represents the number of softballs he bought, then write an equation in standard form, \displaystyle Ax+By=CAx+By=C that represents this situation. Don't use \displaystyle == . Use inequality symbols instead.
Mathematics
1 answer:
marusya05 [52]3 years ago
5 0

Answer:

5x+4y<=20

Step-by-step explanation:

We are expected to model the expression for the cost of the softball and the Hardball combined.

le the number of hardballs be x

let  the number of softs balls be y

 the cost of the hardballs is =5x

  the cost of softball is =4y

therefore given that the total cost is =$20

the expression for the cost of x and y balls is given as

5x+4y<=20

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Answer:

Min =120, Max= 150

The first quartile can be calculated with this data:

130, 135, 140, 120, 130, 130

And the middle value is:

Q_1 = \frac{140+120}{2}=130

The median is the value in the 6th position from the dataset ordered and we got:

Median= 135

The third quartile can be calculated with this data:

135 140 140 143 144 150

And the middle value is:

Q_3 = \frac{140+143}{2}=141.5

The five number summary for this case:

Min. 1st Qu.  Median    Mean 3rd Qu.    Max.  

120.0   130.0   135.0   135.6   141.5   150.0

The boxplot is on the figure attached

Step-by-step explanation:

We have the following data given:

130, 135, 140, 120, 130, 130, 144, 143, 140, 130, 150

If we sort the values on increasing order we got:

120 130 130 130 130 135 140 140 143 144 150

The minimum and maximum are:

Min =120, Max= 150

The first quartile can be calculated with this data:

130, 135, 140, 120, 130, 130

And the middle value is:

Q_1 = \frac{140+120}{2}=130

The median is the value in the 6th position from the dataset ordered and we got:

Median= 135

The third quartile can be calculated with this data:

135 140 140 143 144 150

And the middle value is:

Q_3 = \frac{140+143}{2}=141.5

The five number summary for this case:

Min. 1st Qu.  Median    Mean 3rd Qu.    Max.  

120.0   130.0   135.0   135.6   141.5   150.0

The boxplot is on the figure attached

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The value of co-efficient of determination is 0.241.

<h3>What is the relationship between linear co-relation co-efficient and co-efficient of determination ?</h3>

The co-efficient of determination R² is similar to the linear correlation co-efficient.

We can think of co-relation of determination as a percentage. It gives us the data for how much percentage of data will fall within the linear co-relation.The higher the percentage the more data falls within.If the coefficient is 0.5 then 50% of data falls within the linear co-relation.

According to the given question

Linear correlation coefficient is -0.491

∴ Co-efficient of determination is (-.491)² which is equal to 0.241.

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