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iogann1982 [59]
3 years ago
15

Find the H.C.F. of 40 and 60​

Mathematics
2 answers:
QveST [7]3 years ago
8 0
The greatest common factor of 40 and 60 is 20.
aleksandrvk [35]3 years ago
4 0

Answer:

it's answer is 20

Step-by-step explanation:

hope it helps you

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Cathy bought of a gallon of milk. She drank of a gallon.<br> How much milk did she have left?
uysha [10]

Answer:

would it be zero unless she already has another gallon somewhere

Step-by-step explanation:

7 0
2 years ago
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A fair number cube with 1, 2, 3, 4, 5 and 6 on its faces is rolled once. The dot on the number line below represents the probabi
KiRa [710]
I don't see the question.  Sorry :(
4 0
3 years ago
The length of a rectangle is three times it's width. If the perimeter of the rectangle is 64, find its length and width
wlad13 [49]

set up an equation for the perimeter

l = length w = width

2l + 2w = 64

set up another equation as you know the length is 3 times the width

w = 3l

subsitute w = 3l into the 2l + 2w = 64

2l + 2(3l) = 64

solve for l

2l + 6l = 64

8l = 64

<em><u>length</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>8</u></em>

subsitute into w = 3l

w = 3(8)

<em><u>width</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>2</u></em><em><u>4</u></em>

6 0
3 years ago
Use the distributive property to rewrite the expression 3 (2+11)
kolbaska11 [484]

Answer:

3(2+11) = 3x2 + 3x11

Step-by-step explanation:

4 0
2 years ago
A savings and loan association needs information concerning the checking account balances of its local customers. A random sampl
Marina86 [1]

Answer:

The 99% confidence interval for the true mean checking account balance for local customers is ($439.29, $888.99).

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 14 - 1 = 13

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 13 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.99}{2} = 0.995. So we have T = 3.0123

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 3.0123\frac{279.29}{\sqrt{14}} = 224.85

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 664.14 - 224.85 = $439.29

The upper end of the interval is the sample mean added to M. So it is 664.14 + 224.85 = $888.99.

The 99% confidence interval for the true mean checking account balance for local customers is ($439.29, $888.99).

4 0
3 years ago
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