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miv72 [106K]
3 years ago
8

When combining like terms how do you know to add or subtract?

Mathematics
2 answers:
Vesna [10]3 years ago
6 0

Answer:

It’s depends on the sign.

Step-by-step explanation:

For example if your question is 3x+16y-8-7x+8y then the answer would be -4x+24y-8 if they have the same variable look at them as a separate equation.

polet [3.4K]3 years ago
3 0

Answer:

"Like Terms" means that you can add or subtract two terms. For instance, you know that you can add and get 5. You were able to add these two 'terms' ( the '2' and the '3') because they are both numbers! However, you might also know that you cannot 'combine' 2 and x. Since 2 is a number and 'x' is not, they are not like terms.

Basically if its two numbers that are the same, For example (-2x and -4x) and have with the same variables you would add them. If they are like this (5x and -2x) you would subtract them because its a negative and positive number and get ( 3x).

Hope i helped!!!!

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I really need help with this one it's due today!!
baherus [9]

Answer:

-2/3

3/2

Step-by-step explanation:

So to have a line parallel the equation is: m1 = m2, meaning the slope (represented by m in this equation) is equal. So in the equation. 3y = - 2x + 4 you need to simplify the equation by dividing both sides by 3. Which would be like so: y = - 2/3x + 4/3, which the slope will be -2/3.

To be perpindicular you need the slope to be: m1 * m2 = - 1. So because we already know that the slope is -2/3, all we need to do is set up an equation: -2/3 * y = - 1

-2/3y = - 1

multiply both sides by 3/-2

y = 3/2

4 0
3 years ago
(x^-6)^4<br> Someone please help me :)
Anastasy [175]
The answer I came up with was ×^6-4. Just rewrite it. I hope this was helpful.
3 0
3 years ago
(PLEASE HELP) The table below - does it represent an exponential function?
Aliun [14]
Short answer: I don't know, but that doesn't mean I can't give you something that you can decide for yourself.
y = 4*2^(2n - 2) is the pattern.
Go for broke. Try n = 4. You should get 256. Let's try it.
y = 4 * 2^(2*4 - 2)
y = 4 * 2^(8 - 2)
y = 4 * 2^6
y = 4 * 64
y = 256 yup it works.

The other end is just as important. Suppose n = 1
Then y = 4 * 2^(2*1 - 2) = 4 * 2^0 = 4*1 = 4 Both work.

If this formula is correct, we can abbreviate it to make your task easier.
y = 4 * 2^(2n - 2)
y = 2^2 * 2^(2n - 2)
y = 2^(2n - 2 + 2)
y = 2^(2n) Now try the two end points again.

n = 4
y = 2^(2*4)
y  =  2^8
y = 256

n = 1
y = 2^(2*1)
y = 2^2
y = 4 which again checks.

so y = 2^(2n) I think is an exponential function.
Sorry my explanation is so long.

6 0
3 years ago
One month, Jon worked 3 hours less than Chaya, and Angelica worked 4 hours more than Chaya. Together they worked 196 hours. Find
OleMash [197]

джон работал на 1 час меньше

3 0
3 years ago
Read 2 more answers
Here is my question.
s2008m [1.1K]

Answer:

5/8

Step-by-step explanation:

if 1/8 is used for one batch . for five batch=1/8*5=5/8

4 0
3 years ago
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