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nalin [4]
3 years ago
14

Find the slope and initial value of the graph below. Then write the equation of the line. Write the equation of the line.

Mathematics
1 answer:
LenaWriter [7]3 years ago
7 0

Answer:

y= x + 2

Hope this helps.

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The points (0, 5) and (4, 13) lie on the graph of a linear function. What is the rate of change of the function?
Viefleur [7K]
The rate of change is the slope of this line
m = (y2 - y1)/(x2 - x1) = (13 - 5)/(4 - 0) = 8/4 = 2
6 0
3 years ago
Can u pls help me with this thanks
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7 0
3 years ago
Tan Please help I’m on a time limit
Leto [7]

Answer:

8/15

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
I need help with HW it is hard (repost i forgot picture)
creativ13 [48]

Answer:

b 8 hours

Step-by-step explanation:

1/4 is 2 so 2/4 is 4 and we know 3/4 is 6 so 4/4 is 8 which is the answer

4 0
3 years ago
Write the standard form of an equation of an ellipse subject to the given conditions.
irina [24]

Answer:

The answer is below

Step-by-step explanation:

The standard form of the equation of an ellipse with major axis on the y axis is given as:

\frac{(x-h)^2}{b^2} +\frac{(y-k)^2}{a^2} =1

Where (h, k) is the center of the ellipse, (h, k ± a) is the major axis, (h ± b, k) is the minor axis, (h, k ± c) is the foci and c² = a² - b²

Since the minor axis is at (37,0) and (-37,0), hence k = 0, h = 0 and b = 37

Also, the foci is at (0,5) and (0, -5), therefore c = 5

Using c² = a² - b²:

5² = a² - 37²

a² = 37² + 5² = 1369 + 25

a² = 1394

Therefore the equation of the ellipse is:

\frac{x^2}{1369}+ \frac{y^2}{1394} =1

6 0
3 years ago
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