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steposvetlana [31]
3 years ago
10

Which of the following expressions does not have a greatest common monomial factor?

Mathematics
2 answers:
ser-zykov [4K]3 years ago
5 0

Answer:

Step-by-step explanation:

17x²y+8y³-4x²

it has no greatest common monomial factor.

vodka [1.7K]3 years ago
5 0

Answer:

17x²y+8y³-4x²

Step-by-step explanation:

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Find the two partial products in this problem. <br> 1,407x14
Neporo4naja [7]

Answer:

<em>     1,407</em>

<em>x       14</em>

<em>_______</em>

<em>      5,628</em>

<em>+   1,4070</em>

<em>______</em>

  19,698

<em>The two partial products are 5,628 and 14,070</em>

7 0
3 years ago
For the following linear system, put the augmented coefficient matrix into reduced row-echelon form.
Anni [7]

Answer:

The reduced row-echelon form of the linear system is \left[\begin{array}{cccc}1&0&-5&0\\0&1&3&0\\0&0&0&1\end{array}\right]

Step-by-step explanation:

We will solve the original system of linear equations by performing a sequence of the following elementary row operations on the augmented matrix:

  1. Interchange two rows
  2. Multiply one row by a nonzero number
  3. Add a multiple of one row to a different row

To find the reduced row-echelon form of this augmented matrix

\left[\begin{array}{cccc}2&3&-1&14\\1&2&1&4\\5&9&2&7\end{array}\right]

You need to follow these steps:

  • Divide row 1 by 2 \left(R_1=\frac{R_1}{2}\right)

\left[\begin{array}{cccc}1&3/2&-1/2&7\\1&2&1&4\\5&9&2&7\end{array}\right]

  • Subtract row 1 from row 2 \left(R_2=R_2-R_1\right)

\left[\begin{array}{cccc}1&3/2&-1/2&7\\0&1/2&3/2&-3\\5&9&2&7\end{array}\right]

  • Subtract row 1 multiplied by 5 from row 3 \left(R_3=R_3-\left(5\right)R_1\right)

\left[\begin{array}{cccc}1&3/2&-1/2&7\\0&1/2&3/2&-3\\0&3/9&9/2&-28\end{array}\right]

  • Subtract row 2 multiplied by 3 from row 1 \left(R_1=R_1-\left(3\right)R_2\right)

\left[\begin{array}{cccc}1&0&-5&16\\0&1/2&3/2&-3\\0&3/9&9/2&-28\end{array}\right]

  • Subtract row 2 multiplied by 3 from row 3 \left(R_3=R_3-\left(3\right)R_2\right)

\left[\begin{array}{cccc}1&0&-5&16\\0&1/2&3/2&-3\\0&0&0&-19\end{array}\right]

  • Multiply row 2 by 2 \left(R_2=\left(2\right)R_2\right)

\left[\begin{array}{cccc}1&0&-5&16\\0&2&3&-6\\0&0&0&-19\end{array}\right]

  • Divide row 3 by −19 \left(R_3=\frac{R_3}{-19}\right)

\left[\begin{array}{cccc}1&0&-5&16\\0&2&3&-6\\0&0&0&1\end{array}\right]

  • Subtract row 3 multiplied by 16 from row 1 \left(R_1=R_1-\left(16\right)R_3\right)

\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&-6\\0&0&0&1\end{array}\right]

  • Add row 3 multiplied by 6 to row 2 \left(R_2=R_2+\left(6\right)R_3\right)

\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&0\\0&0&0&1\end{array}\right]

8 0
3 years ago
What is the factor for 30n-40
nikitadnepr [17]
Factor: 
<span>30n - 40 = 10(3n - 4)

hope it helps</span>
7 0
3 years ago
okay, genuinely does anyone know how this work? if you do could you please explain how you get the answer-
fomenos

Answer:

The pdf is not showing anything

Step-by-step explanation:I would help you otherwise.I am sorry.Don't let this get you down.I hope you have a good day.

4 0
3 years ago
it takes 18 3/8 inches of wood to make a frame for a small picture if Ms Jones has 108 inches of wood how many frames can she ma
scZoUnD [109]
It would make 5 complete frames, and about 8/10 of another frame.
108 / 18.375 = 5.8&*)&^&%*$*
I used a calculator.
You could keep adding 18 and 3/8 over and over again until you get right under 108 if you're good at math like me, but most people would have to add 18 and 3/8 separately.

Thanks, and if you liked my answer, please consider giving me the brainliest answer, because I need 5 of them to get to the next level.
6 0
4 years ago
Read 2 more answers
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