Using the asymptote concept, we have that:
- The vertical asymptote is x = 9.
- The horizontal asymptote is y = 3.
- The end behavior is that as
.
<h3>What are the asymptotes of a function f(x)?</h3>
- The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator.
- The horizontal asymptote is the value of f(x) as x goes to infinity, as long as this value is different of infinity.
In this problem, the function is:
For the vertical asymptote, we have that:
x - 9 = 0 -> x = 9.
For the horizontal asymptote:
Hence, the end behavior is that as .
More can be learned about asymptotes at brainly.com/question/16948935
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Answer:
a) P(X∩Y) = 0.2
b) 
= 0.16
c) P = 0.47
Step-by-step explanation:
Let's call X the event that the motorist must stop at the first signal and Y the event that the motorist must stop at the second signal.
So, P(X) = 0.36, P(Y) = 0.51 and P(X∪Y) = 0.67
Then, the probability P(X∩Y) that the motorist must stop at both signal can be calculated as:
P(X∩Y) = P(X) + P(Y) - P(X∪Y)
P(X∩Y) = 0.36 + 0.51 - 0.67
P(X∩Y) = 0.2
On the other hand, the probability that he must stop at the first signal but not at the second one can be calculated as:
= P(X) - P(X∩Y)
= 0.36 - 0.2 = 0.16
At the same way, the probability 
that he must stop at the second signal but not at the first one can be calculated as:
= P(Y) - P(X∩Y)
= 0.51 - 0.2 = 0.31
So, the probability that he must stop at exactly one signal is:
Answer:
A
Step-by-step explanation:
because the -2 is where the point is and the slope will start there so when you draw a line the line will pass by (0,-2)
Add v to both sides: -E=2+V
Divide both sides by -1: E= -2-V
Answer: -V-2
Answer:
1320
Step-by-step explanation:
This can be solved using something called a permutation. There are 12 possible swimmers that can be in first place. After that, there are 11 swimmers left to be in second place. Finally there are 10 swimmers left for third place. Multiplying these together, you get 12*11*10=1320 ways. Hope this helps!
