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3 years ago

Change the following Expression in to words 4 ( 2 + 7 )

Mathematics

2 answers:

luda_lava [24]3 years ago

7 0

Answer:

The product of 2 plus 7 multiplied by 4

Step-by-step explanation:

almond37 [142]3 years ago

4 0

Answer:

4(2+7)

8+28=38

Step-by-step explanation:

four into bracket 2+7 close bracket

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What is the solution to the equation below? 5 - n/2 = 12

Zarrin [17]

Step-by-step explanation:

5 - n/2 = 12

10/2 - n/2 = 12

n = (12 × (-2)) + 10

n = (-24) + 10

n = -14

Let's prove it :

$5 - ( - \frac{14}{2} ) \\ = \frac{10}{2} + \frac{14}{2} \\ = \frac{24}{2} \\ = 12$

Conclusion :

5 - n/2 = 12

5 - (-14/2) = 12

and

n = -14

8 0

3 years ago

Paul tosses a quarter off the Main Street bridge into the St. John’s River. The

IRINA_888 [86]

C because maximum height of a quarter

4 0

3 years ago

In the year 2000, the average cost of a computer could be modeled by the equation C = -5t2 + 750, where t is the number of years

elena55 [62]

Answer:

$\Delta C=-5t^2-250$

Step-by-step explanation:

Given:

The average cost of a computer in the year 2000 is given as:

$C=-5t^2+750$

The average cost of a computer in the year 2008 is given as:

$C=-10t^2+500$

Now, the difference in average cost between the years 2008 and 2000 can be calculated by subtracting the average cost in 2000 from the average cost in 2008.

Framing in equation form, we get:

Difference in average cost (ΔC) is given as:

$\Delta C=C_{2008}-C_{2000}\\\\\Delta C= (-10t^2+500)-(-5t^2+750)\\\\\textrm{Distributing the megative sign inside the second polynomial, we get:}\\\\\Delta C=-10t^2+500+5t^2-750\\\\\textrm{Grouping like terms, we get}\\\\\Delta C=(-10t^2+5t^2)+(500-750)\\\\\Delta C=-5t^2-250$