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g100num [7]
3 years ago
14

How do I solve part A

Mathematics
1 answer:
seraphim [82]3 years ago
4 0

Answer:

The solution of this expression is x_{1} = -1 and x_{2} = -\frac{1}{2}.

Step-by-step explanation:

The procedure for solution of exercise A is described below:

1) We expand the expression.

2) The resulting expression is rearranged into the form of a second order polynomial.

3) Roots are found by Quadratic Formula.

Step 1:

2\cdot x \cdot (x+1.5) = -1

2\cdot (x^{2}+1.5\cdot x) = -1

2\cdot x^{2} + 3\cdot x = -1

Step 2:

2\cdot x^{2}+3\cdot x +1 = 0

Step 3:

x_{1, 2} = \frac{-3\pm \sqrt{3^{2}-4\cdot (2)\cdot (1)}}{2\cdot (2)}

x_{1,2} = -\frac{3}{4}\pm \frac{1}{4}

x_{1,2} = \frac{-3\pm 1}{4}

The solution of this expression is x_{1} = -1 and x_{2} = -\frac{1}{2}.

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<h3>How to compute the values?</h3>

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<u>Complete question:</u>

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