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Genrish500 [490]
3 years ago
12

we need to make a number code with 4 digits. how many codes have at least two equal digits? and how many codes have exactly 3 eq

ual digits?
Mathematics
1 answer:
Blizzard [7]3 years ago
6 0

Answer:

First do the case in which none of the digits is 0.

There are 9 ways to choose the digit that repeats 3 times and 8 ways to pick the other, after this there are 4 ways to order the digits. So 9×8×4.

Now we look at the cases in which the digit 0 repeats 3 times. Clearly the 9 numbers are 1000,2000,3000,…,9000.

Lastly we look at the cases in which 0 appears once. There are 9 ways to pick the other digit and 3 ways to order.

So the final answer is 9×8×4+9+9×3.

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A pitcher holds 16 cups of lemonade. How many pints does it hold? 32 8 4 2
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Answer:

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Step-by-step explanation:

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Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar. Chris is playing a
alisha [4.7K]

Let's call the aces h, d, c, s for hearts, diamonds, clubs and spades. So, h, d are red and [ted] c, s[/tex] are black.

Since the first card is replaced, the two picks are identical. This means that the sample space is given by all the possible couple

(x,y)\, x, y \in \{h,d,c,s\}

There are 16 such couples (we have four choices for the first card, and the same four choices for the second card). Now let's compute the odds in our favour to deduce the probability of winning:

If we want a player to draw two card of the same colour, the following couples are good:

(h,h),\ (h,d),\ (d,h),\ (d,d),\ (c,c),\ (c,s),\ (s,c),\ (s,s)

so 8 possible couples over 16. This means that the probability that a player draws two cards of the same color is 8/16 = 1/2.

Similarly, the probability of drawing a red ace first and then a black ace is represented by the following couples:

(h,c),\ (h,s),\ (d,c),\ (d,s)

which are 4 over the same 16 as above, thus leading to a probability of 4/16 = 1/4.

4 0
3 years ago
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((3.55)^2+(4.12)^2+(4.41)^2)/2(3.55)*(4.12)
WINSTONCH [101]

Answer:

((3.55)^2+(4.12)^2+(4.41)^2)/2(3.55)*(4.12)

<u>=358.519825</u>

Step-by-step explanation:

I just used this website called mathpapa.com, extremely useful for algebra calculations. Here's the link if you need it

https://www.mathpapa.com/algebra-calculator.html

8 0
2 years ago
Someone please help me
nadezda [96]

Answer:

Quadrilateral ABCD is a rectangle (more specifically a square)

Quadrilateral WXYZ is not a rectangle

Step-by-step explanation:

A rectangle is a quadrilateral with four straight sides, two sets of parallel sides, and four right angles. Quadrilateral ABCD is a rectangle because it fits all of the criteria. Quadrilateral WXYZ is not a rectangle because it does not have four straight sides or four right angles.

4 0
3 years ago
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kakasveta [241]

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Now that we know the upper quartile, you will also draw a line on that value. Feel free to connect the lines to make the "box".

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Hope this helps and if you have any further questions, please let me know! :)

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