Using the normal distribution, it is found that 95.65% of full term newborn female infants with a head circumference between 31 cm and 36 cm.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean
and standard deviation
is given by:

- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
The mean and the standard deviation are given, respectively, by:

The proportion of full term newborn female infants with a head circumference between 31 cm and 36 cm is the <u>p-value of Z when X = 36 subtracted by the p-value of Z when X = 31</u>, hence:
X = 36:


Z = 1.83
Z = 1.83 has a p-value of 0.9664.
X = 31:


Z = -2.33
Z = -2.33 has a p-value of 0.0099.
0.9664 - 0.0099 = 0.9565.
0.9565 = 95.65% of full term newborn female infants with a head circumference between 31 cm and 36 cm.
More can be learned about the normal distribution at brainly.com/question/24537145
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Answer:
Area of the rhombus, A = 22.5 sq. ft.
Step-by-step explanation:
The area of a rhombus = a. b
where, a = side of the rhombus
and b = height of the rhombus.
Here, the side, a = 5 ft
Height, b = 4.5 ft.
Therefore, area, A = 5 X 4.5 sq. ft
⇒ A = 22.5 sq. ft which is the required answer.
Step-by-step explanation:
1 300 × 2.95/100× 4 = $153.40
Answer: 2nd option
Step-by-step explanation: