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erica [24]
3 years ago
13

Sailors once used a unit of length called a fathom to measure the depth of the water. Each fathom is equal to 6 feet. Which equa

tion represents the relationship between x, the depth of water in fathoms, and y, the depth of the water in feet?
Mathematics
1 answer:
ss7ja [257]3 years ago
3 0

Answer:

y = x*(6 feet/1 fathom)

Step-by-step explanation:

We know the relation:

1 fathom = 6 feet.

We can write:

1 = (6 feet/1 fathom)

Now, remember that any number multiplied by 1 does not change.

Then suppose that we have a measure of 3 fathoms, then:

3 fathoms = (3 fathoms)*1

= (3 fathoms)*((6 feet/1 fathom)) = (3 fathoms/1 fathom)*(6feet)

= 3*(6 feet) = 18 feet.

So we changed the units by multiplying the original measure by  (6 feet/1 fathom)

Then, if x is the depth of water in fathoms and y is the depth of the water in feet, we can write:

y = x*(6 feet/1 fathom)

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Mice21 [21]

Answer:

B. is greater than

Step-by-step explanation:

As the graph of function f(x) is a parabola, so that the equation of function f(x) is: f(x) = ax^{2} +bx+c

As it can be seen in thee figure, the graph of function f(x) cross points (0;8) ;(-2; 0) and (4;0)

=> f(0) = 8; f(-2) = 0; f(4) = 0

We have:

  • f(x=0) = a x 0 + b x 0 + c = 8  => c = 8
  • f (x=-2) = a(-2)^{2} -2b+c = 4a -2b + 8 = 0
  • f (x=4) = a(4)^{2} +4b +c = 16a + 4b + 8 = 0

We have:

+) 4a -2b + 8 = 0 => 2 x (4a -2b + 8) = 8a - 4b + 16 = 0 (1)

+) 16a + 4b + 8 = 0 (2)

We take (2) minus (1)

=> (16a + 4b + 8) - (8a - 4b + 16) = 0

=> 8a - 8 = 0 => a = 1

Replace a = 1 into (1)

=> 8 x 1 - 4b + 16 = 0 => b = 6

So that:  f(x) = x^{2} + 6x +8

f (2) = 2^2 + 6 x 2 + 8 = 24

g (2) = 3 -2 + 2 = 3

<em>=> f(2) is greater than g(2)</em>

5 0
3 years ago
Tile Math INC. is the new "hip" file company in town. Bass Pro Shop Headquarters in
Marizza181 [45]

Answer:

The Hendecagon

Step-by-step explanation:

The area of the Hendecagon is 758.617 ft^2,

758.617 * $3 = $2,275.85

The area of the Nonagon is 748.001 ft^2

748.001 * $4.5 = $3,366.00

3 0
3 years ago
two coins and one six sided number cube are tossed together. What is the probability of getting two heads and a four?
Elis [28]

Answer:

The probability of getting two heads and a four is 1/24

Step-by-step explanation:

The probability of getting a head upon a single toss of a coin, assuming the coin is fair is 1/2.

The probability of getting two heads upon tossing two coins together will simply be the product of the individual probabilities;

P (HH) = 1/2 * 1/2 = 1/4

On the other hand, the probability of getting a four upon rolling a six sided number cube is;

1/6

This is because the number 4 occurs only once in a total possible of 6 numbers.

Therefore, the probability of getting two heads and a four;

P (HH4) = 1/2 * 1/2 * 1/6 = 1/24 since the three events are independent.

4 0
3 years ago
The length of segment TQ= 29. explain how to find the length of segment QV. make sure to put the sentence in this form. statemen
Artyom0805 [142]

Answer:

Length of segment QV = 35 units

Step-by-step explanation:

As shown in the figure attached,

Diagonals of TQVS are perpendicular to each other. Therefore TQVS will be a kite. By the property of a kite,

"There are two pairs of the sides which are equal in measure."

Therefore, TS ≅ TQ and SV ≅QV

Since TS ≅ TQ,

3x + 2 = 29 [Given: TQ = 29 units]

3x = 29 - 2

3x = 27

x = 9

Another pair of the consecutive sides is,

SV ≅ QV ≅ (4x - 1)

By substituting the value of x,

QV = (4 × 9) - 1

     = 36 - 1

     = 35 units

Therefore, length of segment QV = 35 units

3 0
4 years ago
Find the angles in the image
Rama09 [41]

Answer:

  • a) 36°, b) 36°, c) 72°

Step-by-step explanation:

<h3>Given:</h3>
  • PT║VW and SR is transversal
  • m∠PQR = 36°
<h3>To find:</h3>
  • a) m∠SQT
  • b) m∠QRW
  • c) m∠PRV
<h3>Solution</h3>

a) ∠SQT is vertical with ∠PQR and therefore has equal measure

  • m∠SQT = 36°

b) ∠QRW is corresponding angle with ∠SQT and therefore has equal measure

  • m∠QRW = 36°

c) m∠PRV = m∠PRQ as marked equal

  • m∠PRV +m∠PRQ + m∠QRW = 180° as straight angle
  • m∠PRV*2 = 180° - 36°
  • m∠PRV*2 =144°
  • m∠PRV = 144°/2
  • m∠PRV = 72°
8 0
3 years ago
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