Answer: Reach and frequency
Explanation:
The media strategy is the planning and action that basically involve high reach in the exposure by using the media vehicle. It basically improve the overall conversation rate of customers.
The conversation rate is refers to the total percentage of the users which involve using the website and various applications.
This strategy also involve with high frequency that limited the list of the media vehicle.
Answer:
filler content
Explanation:
Isabel must use some sort of filler content while creating a wireframe that she is up with. For the banner, she can make use of the placeholder, and for the text, she can make use of the lorem ipsum. Also, if the wireframe is low fidelity then only she can use above. And if the wireframe is high fidelity then she should use the original banner and text.
Answer:
Design a web page that automatically tracks the location to determine the language
Explanation:
I guess the correct answer is Frontal Lobes
Thе frοntal lοbе is thе part οf thе brain that cοntrοls impοrtant cοgnitivе skills in humans, such as еmοtiοnal еxprеssiοn, prοblеm sοlving, mеmοry, languagе, judgmеnt, and sеxual bеhaviοrs. It is, in еssеncе, thе “cοntrοl panеl” οf οur pеrsοnality and οur ability tο cοmmunicatе.
Answer:
// program in C.
// headers
#include <stdio.h>
// headers
#include <stdlib.h>
// headers
#include <limits.h>
// main function
int main(int argc, char** argv)
{
// read value of N from command line arguments
int N=atoi(argv[1]);
// variables
int max=INT_MIN;
// variable
int min=INT_MAX;
int rA[N],i;
// fill the array with random number
for(i=0;i<N;i++)
{
// generate random number from -50 to +50
rA[i]=rand()%101-50;
// find the Maximum
if(rA[i]>max)
max=rA[i];
// find the Minimum
if(rA[i]<min)
min=rA[i];
}
// print values of array
printf("values of the array are:");
for(i=0;i<N;i++)
{
printf("%d ",rA[i]);
}
// print Maximum
printf("\nMaximum value is:%d",max);
// print Minimum
printf("\nMinimum value is:%d",min);
return 0;
}
Explanation:
Read value of N from command line.Then create an array of size N.Fill the array with random number from -50 to +50.Then find the Maximum of all the elements and assign it to variable "max" and find Minimum from all and assign it to variable "min". then print all the elements of the array, Minimum and Maximum.
Output:
command line argument=10
values of the array are:-18 -18 4 -38 2 6 -42 -20 -6 44 -6 -11 15 -31 1
Maximum value is:44
Minimum value is:-42
