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My name is Ann [436]
3 years ago
9

Assuming dataFile is an ofstream object associated with a disk file named payroll.dat, which of the following statements would w

rite the value of the salary variable to the file
A) cout < B) ofstream C) dataFile << salary;
D) payroll.dat <
Computers and Technology
1 answer:
svet-max [94.6K]3 years ago
8 0

Answer:

dataFile << salary;

Explanation:

To write salary to a file (payroll.dat) using ofstream, you make use of the following instruction:

<em>ofstream dataFile; </em>

<em>myfile.open ("payroll.dat"); </em>

<em>myfile <<salary; </em>

<em>myfile.close();</em>

<em />

This line creates an instance of ofstream

<em>ofstream dataFile; </em>

This line opens the file payroll.dat

<em>myfile.open ("payroll.dat"); </em>

This is where the exact instruction in the question is done. This writes the value of salary to payroll.dat

<em>myfile <<salary; </em>

This closes the opened file

<em>myfile.close();</em>

<em />

<em />

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What is the purpose of an arraignment?
IgorC [24]

Answer:

At an arraignment, the court officially illuminates a litigant regarding charges contained in a prosecution or data, gives the respondent a duplicate of the charging instrument, and takes the litigant's response to those charges as a request.

Explanation:

5 0
3 years ago
Read 2 more answers
NAND is logically complete. Use only NAND gates to constructgate-level circuits that compute the
Drupady [299]

Answer:

Hi, for this exercise we have two laws to bear in mind:

Morgan's laws

NOT(А).NOT(В) = NOT(A) + NOT (B)

NOT(A) + NOT (B) = NOT(А).NOT(В)

And the table of the Nand

INPUT OUTPUT

A B A NAND B

0 0         1

0 1         1

1 0         1

1 1         0

Let's start!

a.

Input            OUTPUT

A       A     A NAND A

1         1             0

0        0            1

b.

Input            OUTPUT

A       B     (A NAND B ) NAND (A NAND B )

0         0            0

0         1            0

1          0             0

1          1             1

C.

Input            OUTPUT

A       B     (A NAND A ) NAND (B NAND B )

0        0           0

0        1             1

1         0            1

1          1            1

Explanation:

In the first one, we only need one input in this case A and comparing with the truth table we have the not gate

In the second case, we have to negate the AND an as we know how to build a not, we only have to make a nand in the two inputs (A, B) and the make another nand with that output.

In the third case we have that the OR is A + B and we know in base of the morgan's law that:

A + B = NOT(NOT(А).NOT(В))

So, we have to negate the two inputs and after make nand with the two inputs negated.

I hope it's help you.

3 0
3 years ago
Will give Brainiest and stuff to right answer[s].
Aneli [31]
#22 is 1s and 0s, hope that helps a little bit
6 0
3 years ago
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Consider the following sequence, defined from n=2 to 15 (inclusive). Pn=n2−1. Produce a list named primes which only contains va
omeli [17]

Answer:

primes = []

for n in range(2,16):

   pn = n*n - 1

   if is_prime(pn):

       primes.append(pn)

5 0
3 years ago
Which data type is 2.5?
Phoenix [80]

2.5 is a float.

Float stands for floating point. Floating point types are numbers with decimal places. I hope this helps!

6 0
3 years ago
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