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3 years ago

The volume (V) of a cube is 216 cubic Inches. What is the surface area (S) of the cube?

Mathematics

1 answer:

SpyIntel [72]3 years ago

5 0

Answer:

216in^2

Step-by-step explanation:

6*6*6=216

side length is 6

6^2=36

36*6=216

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WILL MARK BRAINLEST IF CORRECT HELP ME OUT

sveta [45]

Answer:

x = 12

Step-by-step explanation:

Equation: 0.52(x) + 0.72(4) = 0.57(x + 4)

0.52(x) + 0.72(4) = 0.57(x + 4) $\longmapsto$ Multiply

0.52x + 2.88 = 0.57x + 2.28 $\longmapsto$ Subtract 0.52x from both sides

2.88 = 0.05x + 2.28 $\longmapsto$ Subtract 2.28 from both sides

0.6 = 0.05x $\longmapsto$ Divide all sides by 0.05

x = 12

-Chetan K

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2 years ago

If f(x) = 2x³ = x² + 3x + 10 and g(x) = x³ + 3x² + 2x + 4, determine when f(x) > g(x).

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2 years ago

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2 years ago

15,000,015,969+5,000,003

Nat2105 [25]

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2 years ago

A College Alcohol Study has interviewed random samples of students at four-year colleges. In the most recent study, 494 of 1000

Vinil7 [7]

Answer:

The 95% confidence interval for the difference between the proportion of women who drink alcohol and the proportion of men who drink alcohol is (-0.102, -0.014) or (-10.2%, -1.4%).

Step-by-step explanation:

We want to calculate the bounds of a 95% confidence interval of the difference between proportions.

For a 95% CI, the critical value for z is z=1.96.

The sample 1 (women), of size n1=1000 has a proportion of p1=0.494.

$p_1=X_1/n_1=494/1000=0.494$

The sample 2 (men), of size n2=1000 has a proportion of p2=0.552.

$p_2=X_2/n_2=552/1000=0.552$

The difference between proportions is (p1-p2)=-0.058.

$p_d=p_1-p_2=0.494-0.552=-0.058$

The pooled proportion, needed to calculate the standard error, is:

$p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{494+552}{1000+1000}=\dfrac{1046}{2000}=0.523$

The estimated standard error of the difference between means is computed using the formula:

$s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.523*0.477}{1000}+\dfrac{0.523*0.477}{1000}}\\\\\\s_{p1-p2}=\sqrt{0.000249+0.000249}=\sqrt{0.000499}=0.022$

Then, the margin of error is:

$MOE=z \cdot s_{p1-p2}=1.96\cdot 0.022=0.0438$

Then, the lower and upper bounds of the confidence interval are:

$LL=(p_1-p_2)-z\cdot s_{p1-p2} = -0.058-0.0438=-0.102\\\\UL=(p_1-p_2)+z\cdot s_{p1-p2}= -0.058+0.0438=-0.014$

The 95% confidence interval for the difference between proportions is (-0.102, -0.014).

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2 years ago