The number of total bytes in memory is 32,000 bytes.
<h3>
How many total bytes in memory?</h3>
We know that the memory is composed of 8k (or 8,000) words of 32 bits each.
To get the total memory, we just need to take the product between the number of words and the memory that each has.
This will give:
8,000*(32 bits) = 256,000 bits.
But we want this in bytes so we need to change the units, remember that:
1 bit = 0.125 byte.
Then we have:
256,000 bits = 256,000*( 0.125 byte) = 32,000 bytes.
The memory has 32,000 bytes in total.
If you want to learn more about changes of units, you can read:
brainly.com/question/9032119
The ball’s speed and direction at the lowest point of trajectory are; 3.1 m/s and swing to the same angle on the other side
<h3>What is the speed at the lowest point?</h3>
We will assume that all of the motion will transfer to Kinetic Energy at the lowest point. Now, the difference in height will be;
Δh = (130 – 130*cos °5) = 0.49 cm
The change in PE is;
ΔP.E = mgΔh
ΔP.E = 9.8m/s² × 0.75kg × 0.049 m
ΔP.E = 0.36015 J
Formula for kinetic energy is;
K.E = ¹/₂*m*v²
From conservation of energy;
K.E = P.E
Thus;
¹/₂* 0.075 * v² = 0.36015
v = √[(0.36015 * 2)/0.075]
v = 3.1 m/s
Thus, the pendulum will swing to the same angle on the other side.
Read more about Speed of Pendulum at; brainly.com/question/17054952
The "Final Solution to the Jewish question"
was the official code name for the murder
of all Jews within reach, which was not
restricted to the European continent.
27.0 g
Explanation:
The density of a substance tells you the mass of exactly one unit of volume of said substance.
In your case, aluminium is said to have a density of
density Al
=
2.70 g
.
cm
−
3
This tells you that every
1 mL
of aluminium has a mass of
2.70 g
.
All you have to do now is use the density of aluminium as a conversion factor to go from cubic centimenters of aluminium to grams
10.0
cm
3
⋅
2.70 g
1
cm
3
=
27.0 g
−−−−−
The answer is rounded to three sig figs.