Answer: Subnet mask
Explanation:
Subnet mask is the type of parameter that should be match in order to form the adjacency for running the OSPFv2. The subnet mask is mainly used to identifying the address of network in the system.
The OSPF enable the router that must form an adjacency with the neighbors before sharing any type of data.
It mainly determine the neighbors links in the OSPF. The OSPFv2 router send the special type of message which is known as hello packet in the network.
Answer:
The required coding for the architect to meet these requirement has been described below.
Explanation:
The following ways will help the architecture to meet the requirement.
Create a reusable SOQLQueries class; specify “With Sharing” on the methods that require user context and “Without Sharing” on the methods requiring system context.
Create a SystemSOQLQueries class and a UserSOQLQueries class; set the “With Sharing” keyword on the UserSOQLQueries class and “Without Sharing” on the SystemSOQLQueries class.
Answer:
the man behind the murder
<em><u>Answer</u></em>
5 hours
<em><u>Explanation</u></em>
The two working together can finish a job in

Also, working alone, one machine would take one hour longer than the other to complete the same job.
Let the slower machine working alone take x hours. Then the faster machine takes x-1 hours to complete the same task working alone.
Their combined rate in terms of x is

This should be equal to 20/9 hours.

Multiply through by;





Factor to get:


It is not feasible for the slower machine to complete the work alone in 4/9 hours if the two will finish in 20/9 hours.
Therefore the slower finish in 5 hours.