Answer:
CI 98 % = ( 3.332 ; 5.668 )
t(c) = 2.9979
Step-by-step explanation:
Confidence Interval CI 98 % then α = 2 % α = 0,02 α/2 = 0.01
Sample information:
Sample size n = 8
sample mean x = 4.5
standard deviation of sample s = 1.1 kg
degree of freedom df = n - 1 df = 8 - 1 df = 7
With α/2 0.01 and df = 7 from t-studente table we find t(c)
t(c) = 2.9979
CI 98 % = ( x ± t(c) * s/√n )
CI 98 % = ( 4.5 ± 2.9979 * 1.1/ √8 )
CI 98 % = ( 4.5 ± 3.2976/2.8228 )
CI 98 % = ( 4.5 ± 1.168 )
CI 98 % = ( 3.332 ; 5.668 )
Answer:
2y+1=0
Step-by-step explanation:
a number one greater than y is y+1
so sum of y and y+1= 2y+1
Answer:
It is not
Step-by-step explanation:
Because "Kira" lol is doing something like saying 1-3 = 2 which it doesn't you have to regroup in this case and you can't do what she did, though what she did with her whole numbers is correct
I hope this helps!
