Hello.
The Manager has concluded that 2 out of 25 light bulbs are faulty.The table he created represents the ratio of bulbs checked and which ones were found faulty.
A way that he could verify that the table is correct is by simplifying each ratio. If each of them turn out to 2:25, then the conclusion is correct.
The best answer that matches this is answer choice "C.)" as it also defines our method of verifying the table's validity (just the order of the ratio is reversed, and that's fine as long as the variables are matching as well). We can further prove that this answer is correct by making ratios of our table and simplifying them;
100:8; divide both sides by 4.
25:2
500:40; divide both sides by 20.
25:2
2,000:160; divide both sides by 80.
25:2
This ratio is always the simplified answer.
Your answer is: "C.)"
I hope this helps!
Answer:
Class Boundary = 1 between the sixth and seventh classes.
Step-by-step explanation:
Lengths (mm) Frequency
1. 140 - 143 1
2. 144 - 147 16
3. 148 - 151 71
4. 152 - 155 108
5. 156 - 159 83
6. 160 - 163 18
7. 164 - 167 3
The class boundary between two classes is the numerical value between the starting value of the higher class, which is 164 for the 7th class in this case, and the ending value of the class of the lower class, which is 163 for the 6th class in this case.
Therefore the class boundary between the sixth and seventh classes
= 164 - 163 = 1
Therefore Class Boundary = 1.
It can be seen that class boundary for the frequency distribution is 1.
If we take the difference between the lower limits of one class and the lower limit of the next class then we will get the class width value.
Therefore, Class width,
w = lower limit of second class - lower limit of first class
= 144 - 140
= 4
Answer:
315
Step-by-step explanation:
The sum of -265 and -156:
-265 + (-156)
= -265-156
= -421
The sum of 356 and -250:
356 + (-250)
= 356-250
= 106
The sum of both:
-421 + 106
= -315
Hope this helped!
Answer:
291666666667/100000000000
