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beks73 [17]
3 years ago
11

PLEASE, SOMEONE, HELP I'LL MARK BRAINLIEST

Mathematics
2 answers:
Serjik [45]3 years ago
8 0

Answer: Under↓↓↓

Took me 10Min =|

Step-by-step explanation:

N.4=9  7/10

N.5=6 3/8

N.6=8 11/12

N.7=9 1/4

N.8=4 1/4

N.9=9 1/2

N.10=13 1/4

N.11=14 7/10

N.12=7 5/12

N.13=10 5/8

N.14=8 1/3

N.15=9 1/2

N.16=6 17/20

N.17=12 5/8

N.18=22 11/16

N.19=5 1/3

N.20=31 1/5

N.21=16 3/4

kondaur [170]3 years ago
6 0

Answer:

You have to find the common denominators then add the numerators

Step-by-step explanation:

But when you find the common denominator dont add them

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Counting numbers are to be formed using only the digits 9, 3, 5, 8, 7, 6, 4, and 1. Determine the number of different possibilit
natulia [17]

Answer:

64.

Step-by-step explanation:

There are 8 digits in the list.

This will be the number of permutations of 2 from 8 plus the duplicate numbers 11, 22 etc.

So we have 8P2 + 8 possibilities.

= 8! / (8-2)! + 8

= 56 + 8

= 64.

7 0
4 years ago
What is the scale factor ? And given that QY’ = 4.125 what is QY?
Drupady [299]

Step-by-step explanation:

Scale factor is found by making a fraction of two numbers;

In this case, 3.5/2, since the dilated line is larger

Scale factor: 1.75 (simplified)

Given that QYprime is 4.125,

4.125 * (2/3.5)

= 2.357 (rounded)

4 0
3 years ago
8. Which of the following are equivalent to 50? Select all that apply. A. 10% of 5,000 B. 20% of 250 C. 25% of 200 D. 30% of 150
Alex

Answer:

B. 20% of 250

would be 50

4 0
3 years ago
The tyre of a car wheel has an outer diameter of 30 cm . How many times will the wheel rotate on a journey of 5 km
faltersainse [42]

Answer:

5305.1647 times

Step-by-step explanation:

The Circumference of a circle : πd

d = diameter of circle = 30 cm

Circumference of wheel = π * 30cm = 94.247779 cm

1km to cm

1km = 100000cm

5 km = 500000 cm

Hence, number of times wheel rotate on a 5km journey :

500000 cm / 94.247779 cm

= 5305.1647 times

3 0
3 years ago
Molly took part in a math quiz and scored 55 points on 30 questions. Of the questions, there were 3-point word problems, 2-point
seropon [69]

Answer:

3\ point\ word = 5

2\ point\ word = 15

1\ point\ word = 10

Step-by-step explanation:

Given

Represent

3-point word with T;

2-point with U and

1-point with V

U = 5 + V --- (1)

If total questions is 30, then

T + U + V = 30 --- (2)

If total points is 55, then

3T + 2U + V = 55 --- (3)

Substitute 5 + V for U in (2) and (3)

T + U + V = 30 --- (2)

T + 5 + V + V = 30

T + 5 + 2V = 30

T + 2V = 25 ---- (4)

3T + 2U + V = 55 --- (3)

3T + 2(5 + V) + V = 55

3T + 10 + 2V + V = 55

3T + 10 + 3V = 55

3T  + 3V = 55 - 10

3T  + 3V = 45

Divide through by 3

T + V = 15 ---- (5)

Subtract (5) from (4)

(T + 2V = 25 )- (T + V = 15)

T - T + 2V - V = 25 - 15

V = 10

Recall that:

U = 5 + V

U = 5 + 10

U = 15

Substitute 10 for V in (5)

T + V = 15

T + 10 = 15

T = 5

3 0
3 years ago
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