Answer:
The distance when x = 6km is D = 498 KM
Step-by-step explanation:
Here, given the formula for the distance, we want to find the distance D given the value of x to be 6km
What we do simply here is to substitute the value 6km as x in the equation
The equation is
D = 4x^3 - 10x^2 -6
Substituting x = 6, we have
D = 4(6^3) -10(6^2) -6
D = 864-360-6
D = 498 km
Answer:
-9
Step-by-step explanation:
2t + 8= -10
2t= -10-8 you bring 8 and it turns to a negative and. then you just minus it negative 10.
2t= -18. you divide both by 2
t= -9
Left Problem: (first attached figure)
a) The vertex is (75, 25)
b) This means the ball reaches a maximum height of 25 feet at a point 75 feet downfield.
c) No, the ball will not be high enough to pass over the goal post. The point representing the goal post is above the path of the ball.
Right Problem: (second attached figure)
a) The vertex is (2.5, 55)
b) It means the ball reaches a maximum height of 55 feet 2.5 seconds after it is launched.
This is a proportion problem.
z 4
--- = ----
12 5
We can cross multiply and divide.
5z = 48
z = 9.6
Hope this helps!
Answer:
1/2
Step-by-step explanation: