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galina1969 [7]
3 years ago
7

100×0.23 = 101×0.23 = 102×0.23 = 103×0.23 =

Mathematics
2 answers:
zaharov [31]3 years ago
7 0

Answer:

100×0.23=23

101×0.23=23.23

102×0.23=23.46

103×0.23=23.69

Inessa05 [86]3 years ago
6 0

Answer:

Step-by-step explanation:

<h2>100×0.23= </h2><h2>Answer:23</h2><h2>101×0.23=</h2><h2>Answer:23.23</h2><h2>102×0.23=</h2><h2>Answer:23.46</h2><h2>103×0.23=</h2><h2>Answer:23.69</h2><h2><u></u></h2><h2 />

<u />

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.. an. v. . it V V is going on afield trip to Austin to of Texas History and lo see an I MAX Ruiz day given the number of hours
erastova [34]
This is one of those problems where you'll sink like a rock if
you allow yourself to be blinded by all the useless, unnecessary,
irrelevant information in the first paragraph.

The ONLY information you need is:

-- You're chartering a bus for 1 day.
-- It costs  $780 .

That's ALL .

(You don't even need to know that the bus has 55 seats.
You might need that for #8 - #12, but not for #6 or #7.)
_________________________

If the people on the trip are going to share the cost of the bus,
then the cost of each share depends on the number of people.

             Less people ==> each one pays more.
             More people ==> each one pays less.

Just like everybody in the office sharing the cost of
a birthday gift for the boss.

#6 and #7 should really be done in the reverse order ...
do #7 before you worry about #6.
Before you can fill in the table in #6, you absolutely need
to have the equation, whether or not you realize it.

The total cost is fixed . . . It's $780 .

If 2 people go on the trip, each one pays  780 / 2 .
If 3 people go on the trip, each one pays  780 / 3 .
If 4 people go on the trip, each one pays  780 / 4 .
If 5 people go on the trip, each one pays  780 / 5 .
.
.
If 10 people go on the trip, each one pays  780 / 10 .
.
.
If 20 people go on the trip, each one pays  780 / 20 .
.
.
If ' n ' people go on the trip, each one pays  780 / n .
.
.  until the bus is full ...
.
If 55 people go on the trip, each one pays  780 / 55 .
.
If 56 people go on the trip, then you need another bus,
and it gets more complicated.

But up to 55, the price per person is (780 / the number of people).

<span>  #7).             P  =  780 / n .

</span>Now, filling in the table in #6 is a piece 'o cake.<span>

</span>5 people. . . . . . . 780 / 5
10 people . . . . . 780 / 10
15 people . . . . . 780 / 15
20 people . . . . . 780 / 20
.
.
etc.

Just don't go past 55 people.  The equation changes after that.

For ANY number of people, even hundreds, and ANY number
of buses, I think the equation looks something like this:

                P  =  (785/n) · [ 1 + int(n/56) ]  .

' int ' means ' the greatest integer in ... ', that is,
                     ' throw away the fractional part of the quotient,
                       and use only the whole number '.


5 0
4 years ago
A square mirror has sides measuring 2 ft less than the sides of a square painting. If the difference between their areas is 32 f
kari74 [83]

Answer:  The side lengths of mirror and painting are 7 ft and 9 ft respectively.

Step-by-step explanation:  Given that a square mirror has sides measuring 2 ft less than the sides of a square painting and the difference between their areas is 32 ft.

We are to find the lengths of the sides of the mirror and the painting.

Let x ft represents the length of the side of mirror. Then, the side length of square painting is (x+2) ft.

According to the given information, we have

\textup{area of painting}-\textup{area of mirror}=32\\\\\Rightarrow (x+2)^2-x^2=32\\\\\Rightarrow x^2+4x+4-x^2=32\\\\\Rightarrow  4x=28\\\\\Rightarrow x=\dfrac{28}{4}\\\\\Rightarrow x=7.

Therefore, the side length of mirror is 7 ft and the side length of painting is (7+2) = 9 ft.

Thus, the side lengths of mirror and painting are 7 ft and 9 ft respectively.

5 0
3 years ago
The table shows the relationship between Megan's earnings and the hours that she worked.
zavuch27 [327]
I got 76 for the missing value
8 0
3 years ago
What is the product?<br> (3x-5)(22-7x+1)
Gelneren [198K]

answer

1. expand the equation

3x(22-7x+1)-5(22-7x+1)

66x-21x²+3x-110+35x-5

104x-21x²-115

6 0
2 years ago
The statistical difference between a process operating at a 5 sigma level and a process operating at a 6 sigma level is markedly
Svet_ta [14]

Answer:

True

Step-by-step explanation:

A six sigma level has a lower and upper specification limits between \\ (\mu - 6\sigma) and \\ (\mu + 6\sigma). It means that the probability of finding no defects in a process is, considering 12 significant figures, for values symmetrically covered for standard deviations from the mean of a normal distribution:

\\ p = F(\mu + 6\sigma) - F(\mu - 6\sigma) = 0.999999998027

For those with defects <em>operating at a 6 sigma level, </em>the probability is:

\\ 1 - p = 1 - 0.999999998027 = 0.000000001973

Similarly, for finding <em>no defects</em> in a 5 sigma level, we have:

\\ p = F(\mu + 5\sigma) - F(\mu - 5\sigma) = 0.999999426697.

The probability of defects is:

\\ 1 - p = 1 - 0.999999426697 = 0.000000573303

Well, the defects present in a six sigma level and a five sigma level are, respectively:

\\ {6\sigma} = 0.000000001973 = 1.973 * 10^{-9} \approx \frac{2}{10^9} \approx \frac{2}{1000000000}

\\ {5\sigma} = 0.000000573303 = 5.73303 * 10^{-7} \approx \frac{6}{10^7} \approx \frac{6}{10000000}  

Then, comparing both fractions, we can confirm that a <em>6 sigma level is markedly different when it comes to the number of defects present:</em>

\\ {6\sigma} \approx \frac{2}{10^9} [1]

\\ {5\sigma} \approx \frac{6}{10^7} = \frac{6}{10^7}*\frac{10^2}{10^2}=\frac{600}{10^9} [2]

Comparing [1] and [2], a six sigma process has <em>2 defects per billion</em> opportunities, whereas a five sigma process has <em>600 defects per billion</em> opportunities.

8 0
3 years ago
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