Cracked:all=3:4
3/4=x/28
cross multiply or times both sides by 28
3*7=x
21=x
21 are cracked (bad deal)
Answer:
1+√2, 1-√2
Step-by-step explanation:
Since there are 2 factors with an y in the expression, i will assume that there was a mistake in the question and in fact the first term was y³. With that change, we will have that
g(y) = y³-3y²-3y+9
In order to find the critical numbers of g we need to derivate it and equalize the derivate to 0. We can easily derivate g since it is a polynomial:
g'(y) = 3y² - 6y-3
Since g'(y) is a quadratic function, we can obtain the zeros using the quadratic formula, where a = 3, b = -6 and c = -3:

Thus

Therefore, the critical numbers of g are 1+√2 and 1-√2.
I beleive that the problem just ask for that. If you want the critical values, then we need to evaluate those numbers in g. i will do it just in case
g(1 + √2) = (1+√2)³ - 3(1+√2) - 3(1+√2) + 9 = -1.65685
g(1- √2) = (1-√2)³ - 3(1-√2)² -3(1-√2)+9 = 9.6566
Answer:
false
Step-by-step explanation:
adjacent angles should share a common arm and a common vertex. no arms are common and vertex of first angle is CAB whereas the vertex of second angle is DAE
Answer:
Step-by-step explanation:
c + f = 10 (the coach tickets + first class tickets = 10)...there is 10 people
160c + 1230f = 6950....each coach ticket is 160 and each first class ticket is 1230.....and when added, they equal 6950 (for the airfare)
c + f = 10.....c = 10 - f
160c + 1230f = 6950
sub in 10 - f for c
160(10 - f) + 1230f = 6950
distribute the 160 thru the parenthesis
1600 - 160f + 1230f = 6950
combine like terms
1600 + 1070f = 6950
subtract 1600 from both sides
1070f = 6950 - 1600
1070f = 5350
divide both sides by 1070
f = 5350/1070
f = 5 <===== she bought 5 first class tickets
c + f = 10
we found f to be 5...so sub in 5 for f and find c, the coach tickets
c + 5 = 10
c = 10 - 5
c = 5 .......and she bought 5 coach tickets
check...
160c + 1230f = 6950
160(5) + 1230(5) = 6950
800 + 6150 = 6950
6950 = 6950 (correct)....so it checks out
5 coach and 5 first class
Answer:
impossible?
Step-by-step explanation: