First you have to distribute. -3y +12=18. -3y=6. y= -2.
4y + 5 = -31
4y +(5 minus 5) = -31 minus 5 (in affect move the 5 "over")
4y =-36 ( - 31 minus 5 = -36)
4y/4 = -36/4 (divide the 4 from both sides)
y= -9 (-36 divide by 4 = -9)
hope this helps
All you do is multiply 300*.27=
81
I would say did not pass
passed vs did not pass
the first one refers to if she took it or not which was assumed in the first statemtn
the 2nd one is kind of in the midle, it isn't a negation, but it is a partial negatiion
3rd is like the first, the statemtnet doesn't mention attendance
4th is right, passed vs did not pass
answer is Maria did not pass the English exam
Answer:
The fourth pair of statement is true.
9∈A, and 9∈B.
Step-by-step explanation:
Given that,
U={x| x is real number}
A={x| x∈ U and x+2>10}
B={x| x∈ U and 2x>10}
If 5∈ A, Then it will be satisfies x+2>10 , but 5+2<10.
Similarly, If 5∈ B, Then it will be satisfies 2x>10 , but 2.5=10.
So, 5∉A, and 5∉B.
If 6∈ A, Then it will be satisfies x+2>10 , but 6+2<10.
Similarly, If 6∈ B, Then it will be satisfies 2x>10 , and 2.6=12>10.
So, 6∉A, and 6∈B.
If 8∈ A, Then it will be satisfies x+2>10 , but 8+2=10.
Similarly, If 8∈ B, Then it will be satisfies 2x>10. 2.8=16>10.
So, 8∉A, and 8∈B.
If 9∈ A, Then it will be satisfies x+2>10 , but 9+2=11>10.
Similarly, If 9∈ B, Then it will be satisfies 2x>10. 2.9=18>10.
So, 9∈A, and 9∈B.