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aleksandrvk [35]
2 years ago
6

36a2bx2 - 12a²bx + 108a²b

Mathematics
1 answer:
Arisa [49]2 years ago
6 0

Step-by-step explanation:

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Find the area of each composite figure.<br> Round to the nearest TENTH if necessary.
bagirrra123 [75]

Answer:

33

Step-by-step explanation:

split it in to two shape 3*7 and 6*2

7*3=21

6*2=12

21+12=33

4 0
3 years ago
Gemma wants to draw a triangle with side lengths of 4 inches, 12 inches, and 17 inches. Which statement is true? This triangle e
OLga [1]
<span>Answer:This triangle does not exist because the sum of 4 and 12 is less than 17.

Since 4+12 isnt greater than 17, the triangle doesn't exist</span>
6 0
3 years ago
Read 2 more answers
Find the value of given expression <br><br>=》<br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B901%20-%205%20%2B%204%7D%20" id=
Hitman42 [59]

Step-by-step explanation:

Answer is 30 I hope this help you

6 0
2 years ago
Helppp plsssss!!! Show your work!!<br><br>Thanks
ZanzabumX [31]

First, determine if the boundary line should be dotted or solid. In this case, it should be dotted because the symbol is less than not less than or equal to. This leaves you with options B or D. Now, to see if it should be shaded up or down, test it by substituting any point, let's say the origin (0,0), to see if that point is a solution to the equation. If it is, you shade that side of the graph, but if it's not, you shade the other side of the graph.

0 is less than (-3/4)(0) + 2

0 is less than 2.

Because 0 is actually less than 2, the statement is correct and you shade below the line

Answer: D

6 0
3 years ago
A circle is defined by the equation x2 + y2 + 8x + 22y + 37 = 0. What are the coordinates for the center of the circle and the l
inn [45]
We can say that:
8x = -2ax
8 = -2a
a = -4

22y = - 2by
22 = -2b
b = -11

37 = a² + b² - r²
37 = (-4)² + (-11)² - r²
r² = 16 + 121 - 37
r² = 100
r = 10

With all this information, we can say that:
The center of the circle is: (-4 ; -11)
and the radius of the circle is r = 10

P.S:
(a - x)² + (b-y)² = r²
a² - 2ax + x² + b² -2by + y² - r² = 0
x² + y² -2ax - 2by + a² + b² - r² = 0

6 0
3 years ago
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