All categories

3 years ago

Determine the value of −14.1 × (-7.33)

Mathematics

1 answer:

Darya [45]3 years ago

8 0

Answer:

Multiply -14.1 by -7.33.103.353 ?

Step-by-step explanation:

Sorry I'm not very good at math hope this helps..

You might be interested in

A rug shaped like a rectangle is 2.5 meters long and 1.8 meters wide what is the perimeter in meters of the rug

Novosadov [1.4K]

Answer:

P = 8.6 m

Step-by-step explanation:

Given that,

The length of a rectangle = 2.5 m

The width of a rectangle = 1.8 m

We need to find the perimeter of the rug. The perimeter of a rectangle is given by :

P=2(l+b)

= 2(2.5+1.8)

= 8.6 m

So, the perimeter of the rug is 8.6 m.

6 0

3 years ago

I need help ASAP! I am offering brainiest to whoever answers the question first!

Viefleur [7K]

Answer:

Step-by-step explanation:

1536(4)(4)=24576

4 0

3 years ago

Yo what’s 11/4 subtracting by 6 and 1/2

Kruka [31]

-3 3/4
Decimal form: -3.75

3 0

3 years ago

Prove that sin3a-cos3a/sina+cosa=2sin2a-1

Sloan [31]

Answer:

$\frac{sin(3a)-cos(3a)}{sin(a)+cos(a)} =2sin(2a)-1$

Step-by-step explanation:

we are given

$\frac{sin(3a)-cos(3a)}{sin(a)+cos(a)} =2sin(2a)-1$

we can simplify left side and make it equal to right side

we can use trig identity

$sin(3a)=3sin(a)-4sin^3(a)$

$cos(3a)=4cos^3(a)-3cos(a)$

now, we can plug values

$\frac{(3sin(a)-4sin^3(a))-(4cos^3(a)-3cos(a))}{sin(a)+cos(a)}$

now, we can simplify

$\frac{3sin(a)-4sin^3(a)-4cos^3(a)+3cos(a)}{sin(a)+cos(a)}$

$\frac{3sin(a)+3cos(a)-4sin^3(a)-4cos^3(a)}{sin(a)+cos(a)}$

$\frac{3(sin(a)+cos(a))-4(sin^3(a)+cos^3(a))}{sin(a)+cos(a)}$

now, we can factor it

$\frac{3(sin(a)+cos(a))-4(sin(a)+cos(a))(sin^2(a)+cos^2(a)-sin(a)cos(a)}{sin(a)+cos(a)}$

$\frac{(sin(a)+cos(a))[3-4(sin^2(a)+cos^2(a)-sin(a)cos(a)]}{sin(a)+cos(a)}$

we can use trig identity

$sin^2(a)+cos^2(a)=1$

$\frac{(sin(a)+cos(a))[3-4(1-sin(a)cos(a)]}{sin(a)+cos(a)}$

we can cancel terms

$=3-4(1-sin(a)cos(a))$

now, we can simplify it further

$=3-4+4sin(a)cos(a))$

$=-1+4sin(a)cos(a))$

$=4sin(a)cos(a)-1$

$=2\times 2sin(a)cos(a)-1$

now, we can use trig identity

$2sin(a)cos(a)=sin(2a)$

we can replace it

$=2sin(2a)-1$

so,

$\frac{sin(3a)-cos(3a)}{sin(a)+cos(a)} =2sin(2a)-1$

7 0

3 years ago

Read 2 more answers

The area of a rectangular wall of a barn is 85 square feet. Its length is 12 feet longer than the width. Find the length and wid

MaRussiya [10]

Answer:

Length = 17 feet, Width = 5 feet

Step-by-step explanation:

Given:

The area of a rectangular wall of a barn is 85 square feet.

Its length is 12 feet longer than the width.

Question asked:

Find the length and width of the wall of the barn.

Solution:

Let width of a rectangular wall of a barn = $x$

<u>As length is 12 feet longer than the width.</u>

Length of a rectangular wall of a barn = $12+x$

As we know:

$Area\ of\ rectangle=length\times breadth$

$85=(12+x)x\\\\85=12x+x^{2} \\$

Subtracting both sides by 85

$x^{2} +12x-85=0\\x^{2} +17x-5x-85=0\\Taking\ common\\x+(x+17)-5x(x+17)=0\\(x+17)(x-5)=0\\x+17=0, x-5=0\\x=-17,x=5$

As width can never be in negative, hence width of a rectangular wall of a barn = $x$ = 5 feet

Length of a rectangular wall of a barn = $12+x=12+5=17\ feet$

Therefore, length and width of the wall of the barn is 17 feet and 5 feet respectively.

4 0

4 years ago