Hello, have a nice day....
Answer:
I made a card, it is a bit blur. I have added its link in the comment too.
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To solve your problem, we can apply Newton's second law of motion.
Fⁿ = ma
<span>Fnet = net force acting on the skier </span>
<span>m = mass of the skier = 53 kg </span>
<span>a = acceleration up the slope </span>
<span>Since velocity is constant then acceleration is zero, hence the above equation becomes </span>
<span>Fnet = 0 </span>
<span>Fnet = F - Wx - f </span>
<span>where </span>
<span>F = force exerted by the tow bar </span>
<span>Wx = component of skier's weight parallel to the incline = 53(9.8)(sin 20) </span>
<span>f = frictional force = 0.160(53)(9.8)(cos 20) </span>
<span>Substituting appropriate values, </span>
<span>F - 53(9.8)(sin 20) - 0.160(53)(9.8)(cos 20) = 0 </span>
<span>and solving for F, </span>
<span>F = 99.55 N </span>
<span>Hope this helps and have a nice day!</span>
