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klasskru [66]
3 years ago
7

A dolphin travels a distance 20 miles up the coastline in 153 minutes.If 1 mile is equal to 1609 meters,then what is the dolphin

s average speed in meters/seconds rounded to the nearest tenth?
Chemistry
1 answer:
Afina-wow [57]3 years ago
4 0

Answer:

The dolphins average speed is 3.51 \frac{meters}{seconds}

Explanation:

First of all, the following rules of three should be applied:

  • If 1 mile is equal to 1609 meters, 20 miles are equal to how many meters?

distance=\frac{20 miles*1609 meters}{1 mile}

distance=32,180 meters

  • If 1 minute is equal to 60 seconds, 153 minutes is equal to how many seconds?

time=\frac{153 minutes*60 seconds}{1 minute}

time= 9,180 seconds

Speed ​​is a physical quantity that expresses the relationship between the space traveled by an object and the time used for it. That is, speed implies the change of position of an object in space within a certain amount of time and is calculated as:

speed=\frac{distance}{time}

So in this case the velocity is calculated as:

speed=\frac{32,180 meters}{9,180 seconds}

Solving, you get:

Speed= 3.51 \frac{meters}{seconds}

<u><em>The dolphins average speed is 3.51 </em></u>\frac{meters}{seconds}<u><em></em></u>

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Which statments regarding the henderson-hasselbalch equation are true?
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Complete question is;

Which statements regarding the Henderson-Hasselbalch equation are true?

1. If the pH of the solution is known as is the pKa for the acid, the ratio of conjugate base to acid can be determined.

2. At pH = pKa for an acid, [conjugate base] = [acid] in solution.

3. At pH > pKa for an acid, the acid will be mostly ionized.

4. At pH < pKa for an acid, the acid will be mostly ionized.

A. All of the listed statements are true. B. 1, 2, and 3 are true.

C. 2, 3, and 4 are true.

D. 1, 2, and 4 are true.

Answer:

B. 1, 2, and 3 are true.

Explanation:

The formula for the Henderson-Hasselbalch equation is:

pH = pka + log₁₀([A^(-)]/[HA])

Where;

PH is acidity of solution

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A^(-) is concentration of conjugate base

HA is concentration of Acid

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pH = pka + log₁₀([A^(-)]/[HA])

pH - pka = log₁₀([A^(-)]/[HA])

10^(pH - pka) = ([A^(-)]/[HA])

Since we can find the ratio as seen, then the statement is true

- For statement 2: At pH = pKa for an acid, [conjugate base] = [acid] in solution;

We will substitute pH for pKa;

pH = pH + log₁₀([A^(-)]/[HA])

This give;

0 = log₁₀([A^(-)]/[HA])

10^(0) = [A^(-)]/[HA]

1 = [A^(-)]/[HA]

Thus; [A^(-)] = [HA]

Thus, the statement is true

- For statement 3: At pH > pKa for an acid, the acid will be mostly ionized;

This means that;

pH - pKa is greater than 0 and thus;

10^(pH - pKa) is greater than 1.

Thus;

[A^(-)]/[HA] > 1

[A^(-)] > [HA]

So more acid is ionized than base.

So the statement is true.

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This means that;

pH - pKa is less than 0 and thus;

10^(pH - pKa) is less than 1.

Thus;

[A^(-)]/[HA] < 1

[A^(-)] < [HA]

So we have more base ionized than acid. So statement is false

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Answer:

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The answer choices are:

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