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Mashutka [201]
3 years ago
5

If the mass of an object is 50Kg and the acceleration is 2 m/s what is the force?

Mathematics
1 answer:
grigory [225]3 years ago
6 0

Answer:

Check pdf

Step-by-step explanation:

Download pdf
You might be interested in
A number y is 3 times greater than a number x. Which equation shows this relationship
vladimir1956 [14]

Answer:

y = 3x

Step-by-step explanation:

y is 3 times greater than x. So to get Y you would have multiply x 3 times. 3x = 3 * x.

6 0
3 years ago
A bag contains 8 blue marbles, 15 red marbles, 10 yellow marbles, and 3 brown marbles. If a marble is randomly selected, what is
nordsb [41]
8 add 15 add 10 add 3
36
So 3/36
8 0
3 years ago
Read 2 more answers
Translate the sentence into an inequality.
AleksandrR [38]

Answer:

-2x + 6 ≥ -30

Step-by-step explanation:

The difference is subtraction, so -

twice a number, so 2x

and 6, so 6

is =

at least 30, so ≥ -30

-2x + 6 ≥ -30

I think this

Sorry if wrong

8 0
3 years ago
Find the length of a rectangle lot with a perimeter of 66 feet if the length is 3 times more than 4 times the width.
ValentinkaMS [17]

Answer:

27 feet

Step-by-step explanation:

We are told in the question that a lot is rectangular in shape

The perimeter of a rectangle

= 2(L + W)

= 2L + 2W

Where

L = Length of the rectangle

W = Width of the rectangle

From the question,

P = 66 feet

The length is 3 times more than 4 times the width

L = 3 + (4 × W)

= 3+ (4W) = 3 + 4W

Hence,

P = 2L + 2W

66 = 2(3 + 4W) + 2W

66 = 6 + 8W + 2W

Collect like terms

66 - 6 = 8W + 2W

60 = 10 W

W = 60/10

W = 6

The Width of the rectangular lot = 6 feet

To find the length

Perimeter = 2L + 2W

Perimeter - 2W = 2L

L = Perimeter - 2W/2

L = 66 - 2(6)/2

L = 66 - 12/2

L = 54/2

L = 27

Therefore the Length of the rectangular lot = 27 feet

8 0
3 years ago
To find the solutions to an equation of the form ax2+bx+c , use the quadratic equation: x=−b±b2−4ac√2a . What are the two soluti
lidiya [134]

Answer:

1.686

Step-by-step explanation:

Given is an quadratic equation as

2x^2-x-4=0

Also we are given the formula for general equation

ax^2+bx+c as

\frac{-b+/-\sqrt{b^2-4ac} }{2a}

Here in our equation we have

a=2\\b=-1\\c=-4

Hence solution would be

\frac{1+\sqrt{1+32} }{4} ,\frac{1-\sqrt{1+32} }{4} \\\frac{1+\sqrt{33} }{4} ,\frac{1-\sqrt{33} }{4}

Greater would be the one with positive square root

\frac{1+\sqrt{33} }{4} \\=1.6861\\=1.686

5 0
4 years ago
Read 2 more answers
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