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3 years ago

If the mass of an object is 50Kg and the acceleration is 2 m/s what is the force?

Mathematics

1 answer:

grigory [225]3 years ago

6 0

Answer:

Check pdf

Step-by-step explanation:

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How many 4/10+7/100=

Mashutka [201]

The answer is 47/100 or it could also be 0.47

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4 years ago

Read 2 more answers

-9 more than a number results in -20

Alona [7]

Answer:

-11

Step-by-step explanation:

-20-(-9)= -11

6 0

3 years ago

An employees hourly raise went up from $10 per hour to $12 per hour. What is the rate of increase?

Anastaziya [24]

20% because:

rate of Increase = ( final - initial ) / initial * 100

rate of increase = ( 12 - 10 ) / 10 * 100

rate of Increase = 2 / 10 * 100

rate of Increase = 20

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3 years ago

Consider the pattern below 5+5/3+

DedPeter [7]

Answer:

5+5/3+3/1+1

Step-by-step explanation:

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4 years ago

Question 20 not yet answered marked out of 1.00 not flaggedflag question question text luna created a trash can in the shape of

Alex Ar [27]

Consider the triangle with sides a=1.6, b=2.3 and c=1.2 feet. You can use cosine theorem twice to find two unknown angles:

$b^2=a^2+c^2-2ac\cos \angle B,\\ (2.3)^2=(1.6)^2+(1.2)^2-2\cdot 1.6\cdot 1.2\cos \angle B,\\ 5.29=2.56+1.44-3.84\cos \angle B,\\ 3.84\cos \angle B=4-5.29=-1.29,\\\cos \angle B=-\dfrac{1.29}{3.84} =-0.336$

Then you can conclude that ∠B is obtuse (because $\cos \angle B$ ) and m∠B=110°.

$c^2=a^2+b^2-2ab\cos \angle C,\\ (1.2)^2=(1.6)^2+(2.3)^2-2\cdot 1.6\cdot 2.3\cos \angle C,\\ 1.44=2.56+5.29-7.36\cos \angle C,\\ 7.36\cos \angle C=7.85-1.44=6.41,\\\cos \angle C=\dfrac{6.41}{7.36} =0.871$ .

Then you can conclude that ∠C is acute (because $\cos \angle C>0$ ) and m∠C=29°.

3. m∠A+m∠B+m∠C=180°, then m∠A=180°-110°-29°=41°.

Answer: m∠A=41° (∠A is opposite to the side a=1.6), m∠B=110° (∠B is opposite to the side b=2.3) and m∠C=29° (∠C is opposite to the side c=1.2)

3 0

3 years ago