3 years ago

PLS SOMEONE HELP QUICK

Mathematics

2 answers:

Lubov Fominskaja [6]3 years ago

4 0

Answer:

the answer is b.

forsale [732]3 years ago

3 0

Answer:

The answer is graph B.) mate

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(48.9, -53.3) (84.6, -19.9) (-62.6, 81.7) (-14.4 ,-42.6) (71.2, -84.1) (71.2, 76.8 ) state the domain

soldi70 [24.7K]

The x values are the first one (and correlate to the domain), so we just have to find the smallest and largest number, which are -62.6 and 84.6 by just looking through the data

6 0

4 years ago

What is the answer to this question

harina [27]

Answer:

The Slope is 1/2

Step-by-step explanation:

Rise/Run

Rise 1

Run 2

5 0

3 years ago

Read 2 more answers

How would you describe the relationship between the real zeros and x-intercepts of the function y=log4^(x-2)

8_murik_8 [283]

Answer:

its D on edg:)))

Step-by-step explanation:

i took the test thingy and got it right;-;

6 0

3 years ago

A 6th grade class did a weekend fitness challenge. Each student set a goal of `75` minutes of fitness. Luca exercised for `54` m

forsale [732]

Answer:

The answer is 72%

Step-by-step explanation:

54 out of 75 is a percentage of 72%.

$\frac{54}{75} = 72$

Mark me brainliest if possible, it's always appreciated!

Hope this helps!

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6 0

2 years ago

Approximate cos (12π/ 13) by using a linear approximation with f (x) = cos x.

Katarina [22]

First pick a value of $x$ close to $\dfrac{12\pi}{13}$ . You should be fine with $x=\pi$ .

The linear approximation of $f(x)$ at $x=c$ is given by

$f(c)\approx f(a)+f'(a)(c-a)$

where $x=a$ is some fixed value close to $x=c$ . You have

$f(x)=\cos x\implies f'(x)=-\sin x$

so

$f\left(\dfrac{12\pi}{13}\right)\approx f(\pi)+f'(\pi)\left(\dfrac{12\pi}{13}-\pi\right)$
$\cos\dfrac{12\pi}{13}\approx\cos\pi-\sin(\pi)\left(-\dfrac\pi{13}\right)$
$\cos\dfrac{12\pi}{13}\approx-1$

The actual value is closer to -0.9709, so the approximation is decent.

4 0

3 years ago