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Zina [86]
3 years ago
14

Write each equation in function notation, then solve the function for the given value.

Mathematics
1 answer:
Alik [6]3 years ago
8 0

Given:

The equation is:

y=-\dfrac{2}{5}x+\dfrac{3}{8}

To find:

The function notation for the given equation and then solve the function for the value x=\dfrac{1}{3}.

Solution:

We have,

y=-\dfrac{2}{5}x+\dfrac{3}{8}

Substitute y=f(x) in the given equation to find the function notation of it.

f(x)=-\dfrac{2}{5}x+\dfrac{3}{8}

Substituting x=\dfrac{1}{3}, we get

f(\dfrac{1}{3})=-\dfrac{2}{5}(\dfrac{1}{3})+\dfrac{3}{8}

f(\dfrac{1}{3})=-\dfrac{2}{15}+\dfrac{3}{8}

f(\dfrac{1}{3})=\dfrac{-16+45}{120}

f(\dfrac{1}{3})=\dfrac{29}{120}

Therefore, the function notation is f(x)=-\dfrac{2}{5}x+\dfrac{3}{8} and the value of the function at x=\dfrac{1}{3} is \dfrac{29}{120}.

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Answer:

1). 0.903547

2). 0.275617

Step-by-step explanation:

It is given :

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ii). k = 10 with the probability of $\frac{1}{4}$

iii). k = 10 with the probability $\frac{1}{2}$

So the probability of at least two person out of the 'n' born people in same month is  = 1 - P (none of the n born in the same month)

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= \frac{1}{4}\times (1-\frac{_{5}^{12}\textrm{P}}{12^5})+\frac{1}{4}\times (1-\frac{_{10}^{12}\textrm{P}}{12^{10}})+\frac{1}{2}\times (1-\frac{_{15}^{12}\textrm{P}}{12^{15}})

= 0.25 \times 0.618056 + 0.25 \times 0.996132 + 0.5 \times 1

= 0.903547

2).P( k = 10|at least 2 share their birthday in same month)

=P(k=10 and at least 2 born in the same month)/P(at least 2 share their birthday in same month)

= $0.25 \times \frac{0.996132}{0.903547}$

= 0.0.275617

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