There are 25 species of trees, each with a known abundances. The question is how many possible ways to randomly select one tree there are.
We should calculate the number of combinations. Combinations, because we select item/s from a collection. In this case, when we select only one item, the combination is also a permutation. From set of n objects we select r. In our case: n=25, r=1.
The equation is: n!/r!(n-r)!= 25!/1!*24!=25*24!/24!=25
There are 25 different outcomes (events).
Answer:
- Rational: 5.39
- Irrational: √29 ≈ 5.39
Step-by-step explanation:
Any number you can write completely that has a value between the given numbers will be a suitable rational number.
There are many ways to find irrational numbers in the given range. You can make one up, such as ...
... 5.3102003000400005000006...
a non-terminating, non-repeating decimal. (This one has a pattern that makes it easy to extend, but that doesn't make it rational.)
Or, you can use roots, logs, trig functions, exponential functions, or any of the other functions we study that have irrational values. You can add, subtract, or combine them in other ways. (tan(70°)+∛20, for example) For this, I chose √29, because that square root is between the given numbers and 29 is not a perfect square.
If the problem is 6r•s•4rt•10rst, then the answer is 240•r^3•s^2•t^2.
41% and 0.41 im not sure for the last one but hope im right !!
2 2/5
1 4/7
3 2/4 when simplified it is 3 1/2
