Help fast i’m bad with math help
1 answer:
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Answer:
256
Step-by-step explanation:
A calculator works well for this.
_____
None of the minus signs are subject to the exponents (because they are not in parentheses, as (-1)^5, for example. Since there are an even number of them in the product, their product is +1 and they can be ignored.
1 to any power is still 1, so the factors (1^n) can be ignored.
After you ignore all of the things that can be ignored, your problem simplifies to ...
(2^2)(2^-3)^-2
The rules of exponents applicable to this are ...
(a^b)^c = a^(b·c)
(a^b)(a^c) = a^(b+c)
Then your product simplifies to ...
(2^2)(2^((-3)(-2)) = (2^2)(2^6)
= 2^(2+6)
= 2^8 = 256
Answer:
a:x=-3
c:x=1
Step-by-step explanation:
The zeros of a function are the values of x for which the value of the function f(x) becomes zero.
In this problem, we have the following function:
Here we want to find the zeros of the function, i.e. the values of x for which
In order to make f(x) equal to zero, either one of the factors or
must be equal to zero.
Therefore, the two zeros can be found by requiring that:
1)
2)
So the correct options are
a:x=-3
c:x=1