PLESSE HELP ME ASAP

⦁ Use both methods to find the distance between the points on the number line.

Vitek1552 [10]

Answer:

4 and 4

Step-by-step explanation:

Method A

1) Method A: Let 2 be the starting point and -2, the finishing one. Counting between 2 and -2, we can count a distance of 4 units. That's the simplest way, but not convenient to great numbers on the Number Line.

Method B:

There is no such thing as a negative distance, as a physical quantity. So this is the reason why we need to compute the absolute value of two numbers, which is simply what was done on Method B.

|2-(-2)|=|4|=4

As we are dealing with absolute values, the order is not relevant after all, the result remains the same. Take a look:

|-2-2|=|-4|=4

That's why the greater (2) or the lesser number (-2) can be the subtrahend (in bold within the brackets.

3 0

3 years ago

The sum of b and 24 18 less than x an amount of a divided by 3

telo118 [61]

Answer:

b+24

x-18

a/3

Step-by-step explanation:

3 0

3 years ago

On a school trip to a theme park, 4 busses each carry 70 students.

DanielleElmas [232]

Answer:

165 Students Have No Made Plans For Lunch.

Step-by-step explanation:

According To the Question,

Given,On a school trip to a theme park, 4 busses each carry 70 students Then Total Number Of Students on a trip is 70×4=280 Students.

And,35% of the students are bringing their own lunch. Thus,35% Of 280 Students is 98 Students. Then Remaining 182 Students not bring their own lunch.

Now, 17 of the students are buying lunch when they get to the theme park. Thus students Who have not made plans for lunch is 182-17⇒165Students

7 0

2 years ago

) One year, professional sports players salaries averaged $1.5 million with a standard deviation of $0.9 million. Suppose a samp

Nutka1998 [239]

Answer:

Probability that the average salary of the 400 players exceeded $1.1 million is 0.99999.

Step-by-step explanation:

We are given that one year, professional sports players salaries averaged $1.5 million with a standard deviation of $0.9 million.

Suppose a sample of 400 major league players was taken.

Let $\bar X$ = sample average salary

The z-score probability distribution for sample mean is given by;

Z = $\frac{ \bar X -\mu}{{\frac{\sigma}{\sqrt{n} } }} }$ ~ N(0,1)

where, $\mu$ = mean salary = $1.5 million

$\sigma$ = standard deviation = $0.9 million

n = sample of players = 400

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

So, probability that the average salary of the 400 players exceeded $1.1 million is given by = P( $\bar X$ > $1.1 million)

P( $\bar X$ > $1.1 million) = P( $\frac{ \bar X -\mu}{{\frac{\sigma}{\sqrt{n} } }} }$ > $\frac{ 1.1-1.5}{{\frac{0.9}{\sqrt{400} } }} }$ ) = P(Z > -8.89) = P(Z < 8.89)

Now, in the z table the maximum value of which probability area is given is for critical value of x = 4.40 as 0.99999. So, we can assume that the above probability also has an area of 0.99999 or nearly close to 1.

Therefore, probability that the average salary of the 400 players exceeded $1.1 million is 0.99999.

4 0

3 years ago

Solve each of the following equations using a method other than the Quadratic Formula.

liraira [26]

Answer:

A)

y^2-6y = 0

or, y(y-6) = 0

or, y = 0 or y = 6

B)

n^2+5n+7 = 7

or, n^2+5n+7-7 = 7-7 ( Subtracting 7 from both sides)

or, n^2+5n = 0

or, n(n+5) = 0

or, n=0 or n= -5

C)

2t^2-14t+3 = 3

or, 2t^2-14t = 0

or, 2t(t-7) = 0

or, t=0 or t=7

D)

1/3x^2+3x-4 = -4

or, 1/3x^2+3x = 0

or, 1/3x(x+9) = 0

or, x=0 or x= -9

E)

Zero is a common solution to each of the equations. This is because each of the equations had a variable outside the parenthesis with an operation of multiplication.

THANK YOU FOR READING.

8 0

2 years ago