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LuckyWell [14K]
3 years ago
13

A two-dimensional array is essentially? A primitive date type A looped data structure

Computers and Technology
1 answer:
notsponge [240]3 years ago
7 0

Answer:

A looped data structure

Explanation:

A two-dimensional array is an array of another array. You can traverse it using nested loops, one to traverse row and one to traverse columns.

You might be interested in
Assume you are using the text's array-based queue and have just instantiated a queue of capacity 10. You enqueue 5 elements and
ASHA 777 [7]

The indices of the internal array elements that hold the remaining elements is c) 2 to 4

<h3>Calculations and Parameters:</h3>

For us to create a capacity of 10 for the queue, we would enqueue:

We would create a queue of capacity 10:

<h3>Queue q(10);</h3>

We add elements/enqueue 5 elements to the queue :

  • q.queueEnqueue(10);
  • q.queueEnqueue(5);
  • q.queueEnqueue(8);
  • q.queueEnqueue(9);
  • q.queueEnqueue(2);

Printing this would give:

q. queueDisplay()

10, 5, 8, 9, 2

Next, we would remove elements/dequeue 2 elements from the queue :

q. queuedequeue();

q. queuedequeue();

Printing it would be:

q. queueDisplay()

8 ,9, 2

Observing this, the deletion/dequeue starts from the front/first index.

The remaining indices of the internal array elements are: 2, 3, 4 or 2 to 4

Read more about arrays and enqueue here:

brainly.com/question/24188935

#SPJ1

3 0
2 years ago
Advantages of python programming language
Sauron [17]

Answer:

Great starter programming language. Overall very powerful but for beginners the more advanced characteristics like GUIs are too complicated. This is coming from personal experience and after first experiencing programming through Python, Javascript is my new favorite.

Explanation:

a great video by code camp titled "Learn Python - Full Course for Beginners [Tutorial]" is a great starting point!

6 0
3 years ago
Create a program which will input data into a pipe one character at a time. Count the number of characters as they are written i
LenKa [72]

Answer:

a)

#include<stdio.h>

#include<stdlib.h>

#include<fcntl.h>

#include<unistd.h>

 

#define BUFSIZE 16

int main(){

   //pipe descriptors

   char msg[BUFSIZE];

   char buf[BUFSIZE];

   int pipefd[2];

   if(pipe(pipefd) == -1){

       //pipe creation error

       perror("pipe");

       exit(EXIT_FAILURE);

   }

   //pipe creation successfull

   //write four messages

   sprintf(msg , "apple");

   write(pipefd[1], msg, BUFSIZE);

   printf("Written %s\n", msg);

   sprintf(msg , "boy");

   write(pipefd[1], msg, BUFSIZE);

   printf("Written %s\n", msg);

   sprintf(msg , "cat");

   write(pipefd[1], msg, BUFSIZE);

   printf("Written %s\n", msg);

   sprintf(msg , "dog");

   write(pipefd[1], msg, BUFSIZE);

   printf("Written %s\n", msg);

   //read

   read(pipefd[0], buf, BUFSIZE);

   printf("Read: %s\n", buf);

   read(pipefd[0], buf, BUFSIZE);

   printf("Read: %s\n", buf);

   read(pipefd[0], buf, BUFSIZE);

   printf("Read: %s\n", buf);

   read(pipefd[0], buf, BUFSIZE);

   printf("Read: %s\n", buf);

   close(pipefd[0]);

   close(pipefd[1]);

   return 0;

}

(b)

#include<stdio.h>

#include<stdlib.h>

#include<fcntl.h>

#include<unistd.h>

#include<wait.h>

#define BUFSIZE 16

int main(){

   //pipe descriptors

   char msg[BUFSIZE];

   char buf[BUFSIZE];

   int pipefd[2];

   if(pipe(pipefd) == -1){

       //pipe creation error

       perror("pipe");

       exit(EXIT_FAILURE);

   }

   //pipe creation successfull

   //write four messages

   if(fork() == 0){

       //this is child

       //close unused write end

       close(pipefd[1]);

       read(pipefd[0], buf, BUFSIZE);

       printf("This is child process reading first message. Content is %s\n", buf);

       read(pipefd[0], buf, BUFSIZE);

       printf("This is child process reading second message. Content is %s\n", buf);

       read(pipefd[0], buf, BUFSIZE);

       printf("This is child process reading third message. Content is %s\n", buf);

       read(pipefd[0], buf, BUFSIZE);

       printf("This is child process reading fourth message. Content is %s\n", buf);

       close(pipefd[0]);

       //exit from child

       exit(EXIT_SUCCESS);

   }

   //this is parent process

   //close unused read end

   close(pipefd[0]);

   sprintf(msg , "apple");

   printf("This is parent process. Writing first message into pipe\n");

   write(pipefd[1], msg, BUFSIZE);

   sprintf(msg , "boy");

   printf("This is parent process. Writing second message into pipe\n");

   write(pipefd[1], msg, BUFSIZE);

   sprintf(msg , "cat");

   printf("This is parent process. Writing third message into pipe\n");

   write(pipefd[1], msg, BUFSIZE);

   sprintf(msg , "dog");

   printf("This is parent process. Writing fourth message into pipe\n");

   write(pipefd[1], msg, BUFSIZE);

   close(pipefd[1]);

   //wait for child

   wait(NULL);

   return 0;

}

(c)

#include<stdio.h>

#include<stdlib.h>

#include<fcntl.h>

#include<unistd.h>

#include<sys/wait.h>

#include<sys/types.h>

#include<signal.h>

typedef struct sigaction Sigaction;

unsigned long long size = 0;

void alarmhandler(int sig){

   //alarm fired writing blocked

   printf("Write blocked after %llu characters\n", size);

   exit(EXIT_SUCCESS);

}

int main(){

   //pipe descriptors

   int pipefd[2];

   if(pipe(pipefd) == -1){

       //pipe creation error

       perror("pipe");

       exit(EXIT_FAILURE);

   }

   //install handler

   sigset_t mask , prev;

   sigemptyset(&mask);

   sigaddset(&mask , SIGALRM);

   sigprocmask(SIG_BLOCK , &mask , &prev);

   Sigaction new_action;

   sigemptyset(&new_action.sa_mask);

   new_action.sa_flags = SA_RESTART;

   new_action.sa_handler = alarmhandler;

   sigaction(SIGALRM , &new_action , NULL);

   sigprocmask(SIG_SETMASK , &prev, NULL);

   while(1){

     

       //print size on multiple of 4

       if(size != 0 && size % 1024 == 0){

           printf("%llu characters in pipe\n", size);

       }

       //reset previous alarm

       alarm(0);

       //set new alarm for 5 seconds

       alarm(5);

       //write to pipe one character

       write(pipefd[1], "A", sizeof(char));

       size++;

   }

   return 0;

}

Explanation:

Output for a, b, c are pasted accordingly

4 0
4 years ago
Please write a complete program to calculate monthly payment given
jasenka [17]

Explanation:

Code with comments:

#include <stdio.h>

#include <math.h>  

/* math library is required to use pow() function

First we need to create a function to calculate the Monthly Payment

It would take three inputs Rate, Years, and Principle amount

Then we converted the Rate and Months according to problem statement

pow() function is used to find (1+R)^M

Then finaly this function returns the value of Monthly Payment  */

float MonthlyPay(float R, int M, int P)

{

    R=R/1200;

    M=M*12;

   float po=pow((1+R),M);

   float PayM=(R+(R/(po-1)))*P;

    return PayM;

}

/*  In the main() function we get 3 inputs from the user Years, Rate and Principle amount

then we call the MonthlyPay function and pass it 3 inputs that we got from the user

then we calculated the total Payment by multiplying the Monthly Pay and total number of months

then we calculated the interest Amount by subtracting the Principle Amount from total Pay

Testing is performed and output result is given at the end and also attached in the image   */

int main(void)

{

    float Rate;

    int Year, Amount;

    printf("Enter Years: ");

    scanf("%d",&Year);

    printf("Enter Rate: ");

    scanf("%f",&Rate);

    printf("Enter Principle Amount: ");

    scanf("%d",&Amount);

   

    float Pay = MonthlyPay(Rate, Year, Amount);

    printf ("Monthly Payment is: %f \n", Pay);

    float totalPay=Pay*Year*12;

    printf ("Total Payment is: %f \n", totalPay);

    float interest=totalPay-Amount;

    printf ("Interest Expense is: %f \n", interest);

    return 0;

}

Output:

Enter Years: 5

Enter Rate: 7

Enter Principle Amount: 12200

Monthly Payment is: 241.572767

Total Payment is: 14494.367188

Interest Expense is: 2294.367188

7 0
3 years ago
When you tried to login to server your trail may faild this failure event is recorded in<br>​
julia-pushkina [17]
Real time not online time...
8 0
3 years ago
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