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denis23 [38]
3 years ago
12

Please help will give brainliest

Mathematics
1 answer:
babymother [125]3 years ago
8 0

Answer:

no

Step-by-step explanation:

[3(a-2) / (a+2)(a-2)] - [6a / (a+2)(a-2)] = -3/(a-2)

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HELPPPPPPPP! Which is true regarding secants and chords?
cricket20 [7]

Answer:

Chords and secants intersect the perimeter of a circle twice. Chords are segments entirely within a circle, while secants are lines or rays that extend through a circle.

Explanation:

A line intersecting a circle in two places is referred to as a secant.  The portion of the secant contained within the circle is called a chord.

This means that both chords and secants intersect the perimeter of a circle twice, chords are entirely inside the circle, and secants extend through a circle to the outside.

3 0
3 years ago
Read 2 more answers
<A and <B are vertical angles. If m<A = (7x - 8)⁰ and m<B = (6x + 17)°, then find the value of x.​
loris [4]

Answer:

x = 25

Step-by-step explanation:

Vertical Angles tell us that they are congruent, so:

7x - 8 = 6x + 17

x - 8 = 17

x = 25

Hope this helps!

8 0
3 years ago
How do i solve x=y+1 and 3x+2y=8 by substitution
Alchen [17]
3(y+1)+2y=8  

3y + 3 +2y = 8

5y +3 = 8
     -3    -3

5y = 5
---    ---
 5      5

y=1
5 0
3 years ago
Which situation can be represented by the equation 4d+5=29
Nitella [24]
Jane spent $29 from online shopping. There’s a one time shipping fee of $5. Jane buys 4 of the same item. How much is the cost of the item?
4 0
3 years ago
The hypotenuse of a triangle is one foot more than twice the length of the shorter leg. The longer leg is seven feet longer than
Serhud [2]
Start by calling the shortest side s. We then know that the longer leg (call it l) is 7 feet longer i.e. l=s+7. We also know that the hypotenuse, h is 1 foot more than twice the short leg i.e. h=2s+1. We now have 3 unknowns but only 2 equations to solve them. Luckily we know this is a right triangle so we can use the Pythagorean Theorem as our third equation:
a^{2}+b^{2}=c^{2}
Substituting known values:
s^{2}+(s+7)^{2}=(2s+1)^{2}
This is now an equation in one variable and can be solved algebraically for s. Back-substitution can then be used for the other sides. 
4 0
3 years ago
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