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3 years ago

I need help with question number 1 and question number 2 please

Mathematics

1 answer:

Ivenika [448]3 years ago

4 0

1. It is a quadratic equation.

Explanation:

A quadratic equation is any equation that can be rearranged in standard form (ax^2 + bx + c). That equation can be rewritten as -x^2 + 1, where a is -1, b is 0, and c is 1.

2. 4x^2, 3x, and 5.

Explanation:

A quadratic term is ax^2 in the formula ax^2 + bx + c. A linear term is bx in the formula, and a constant is c in the formula.

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Find the measure of the line segment TR

vredina [299]

9514 1404 393

Answer:

Step-by-step explanation:

The product of lengths from the point where the secants meet to the near and far circle intersection points is the same for both secants.

RQ·RC = RS·RT

8(27) = (3x)(8x)

9 = x^2 . . . . . . . . . divide by 24

3 = x

Then the length of interest is ...

TR = 8x = 8·3

TR = 24

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3 years ago

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ryzh [129]

Answer:

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Step-by-step explanation:

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3 years ago

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Work out the surface area of this sphere give your answer to 1 decimal place it is 2.6cm

hram777 [196]

Answer:

SA : 84.9cm³

Step-by-step explanation:

Formula : 4×pi×r² as well as 4pi r²

4 x pi x 2.6²=84.94866535

1dp : 84.9

5 0

3 years ago

Can Anyone Help Me

Dmitry_Shevchenko [17]

A. hundreds
250 bars * $2 each = $500

5 0

3 years ago

A certain store sells only T-shirts. Let the random variable X represent the number of T-shirts bought from the store on any day

faltersainse [42]

Answer:

$(a)\ \mu_y = 1125$

$(b)\ \sigma_y = 300$

Step-by-step explanation:

Given

$\mu_x = 75$ -- Mean of T-shirts

$\sigma_x = 20$ -- Standard deviation of T-shirts

$Rate = \$ 15$

Solving (a): The mean of the revenue $(\mu_y)$

To solve this, we use:

$\mu_y = Rate * \mu_x\\$

This gives:

$\mu_y = 15 * 75$

$\mu_y = 1125$

Solving (b): The standard deviation of the revenue $(\sigma_y)$

To solve this, we use:

$\sigma_y = \sqrt{Rate^2 * \sigma_2^2}$

This gives:

$\sigma_y = \sqrt{15^2 * 20^2}$

$\sigma_y = \sqrt{90000}$

$\sigma_y = 300$

7 0

3 years ago