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natita [175]
3 years ago
12

John puts the base of a 13 foot ladder 4 feet from the wall of his house. How far up the wall does the ladder reach? Round your

answer to two decimal places.
Mathematics
1 answer:
antiseptic1488 [7]3 years ago
7 0

Answer:

12.04 feet

Step-by-step explanation:

Applying Pythagoras theorem,

a^{2}= b^{2} + c^{2}

13^{2} =4^{2} + c^{2}

c^{2} = 145

c=\sqrt{145}

c=12.04

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A jet travels 600 miles in 5 hours. At this rate, how far could the jet fly in 15 hours? *
tester [92]

Answer:

7767

Step-by-step explanation:

6878

4 0
3 years ago
A submarine was hovering 500 ft below the surface of the ocean. It rose 125 feet and then descended 225 feet to avoid detection
Vilka [71]

Answer:

600 feet deep

Step-by-step explanation:

The submarine was at 500 feet then it went 125 feet up so 500-125=375 then you take that and add 225 feet so 375+225=600

6 0
3 years ago
Multiply. (2x-1)(3x+5)
Nookie1986 [14]

ANSWER

6x² + 7x - 5

Step-by-step explanation:

(2x-1)(3x+5)

= 6x² + 10x - 3x - 5

= 6x² + 7x - 5

3 0
3 years ago
Read 2 more answers
If you plot and connect these points P1(3,2) and P2(6,8) , what figure is Formed? What is the Direction?
Sergio [31]

Answer:

Please check the explanation.

Step-by-step explanation:

Given the points

  • P1(3, 2)
  • P2(6, 8)

When we plot P1(3, 2) and P2(6, 8), we determine the line segment P1P2.

The direction of the segment is from P1 to P2.

Determining the length of the segment P1P2.

\:l=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

  =\sqrt{\left(6-3\right)^2+\left(8-2\right)^2}

  =\sqrt{3^2+6^2}

  =\sqrt{45}

  =\sqrt{5}\sqrt{3^2}

  =3\sqrt{5}

Thus, the length of the segment is:

\:\:\:l=3\sqrt{5}

Determining the equation of a line containing the segment P1P2

Given the points

  • P1(3, 2)
  • P2(6, 8)

Finding the slope between P1(3, 2) and P2(6, 8)

\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}

\left(x_1,\:y_1\right)=\left(3,\:2\right),\:\left(x_2,\:y_2\right)=\left(6,\:8\right)

m=\frac{8-2}{6-3}

m=2

Using the line point-slope form of the line equation

y-y_1=m\left(x-x_1\right)

where m is the slope of the line and (x₁, y₁) is the point

substituting the values m = 2 and the point (3, 2)

y-2=2\left(x-3\right)

Add 2 to both sides

y-2+2=2\left(x-3\right)+2

y=2x-4

Thus, the equation of a line containing the line segment P1P2 is:

y=2x-4

8 0
3 years ago
I need help i need help
scoundrel [369]
(2,1)
a vertex is the highest or lowest point of a parabola!
hope this helps :)
6 0
3 years ago
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