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3 years ago

Need help plz!!!?!?!?!?

Mathematics

1 answer:

Kipish [7]3 years ago

3 0

Answer:

54yd

Step-by-step explanation:

Area for the rectangle=8×6

=48yrd

area for the triangle=1/2×4×3

=6yd

Total area=48+6=54yd

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Write the quadratic equation in standard form -8x+3x^2=-18

stepladder [879]

X = ± √<span>6 </span><span>= ± 2.4495 because i know it</span>

6 0

2 years ago

write the standard form of the equation of the circle with endpoints of a diameter at the points (9,2) and (-7,5)

AnnyKZ [126]

Answer:

Step-by-step explanation:

Answer:

(x-1)²+(y-3.5)² = 265/4

Step-by-step explanation:

first find the midpoint (center of the circle)

(9+-7)/2, (2+5)/2

(1, 3.5) = center

then distance formula to find diameter

√(9- -7)²+(2-5)²=√256+9 = √265

The radius is half the diameter = (√265)/2

Formula for circle is (x-h)²+(y-k)²=r², where (h, k) is the center

Now you can plug everything in.

(x-1)²+(y-3.5)² = 265/4

4 0

3 years ago

Help please, thank you.

aivan3 [116]

Answer:

Step-by-step explanation:

It's not a function because the X's repeat

8 0

2 years ago

Integrate the following

enot [183]

I suppose you mean to have the entire numerator under the square root?

$\displaystyle\int_2^4\frac{\sqrt{x^2-4}}{x^2}\,\mathrm dx$

We can use a trigonometric substitution to start:

$x=2\sec t\implies\mathrm dx=2\sec t\tan t\,\mathrm dt$

Then for $x=2$ , $t=\sec^{-1}1=0$ ; for $x=4$ , $t=\sec^{-1}2=\frac\pi3$ . So the integral is equivalent to

$\displaystyle\int_0^{\pi/3}\frac{\sqrt{(2\sec t)^2-4}}{(2\sec t)^2}(2\sec t\tan t)\,\mathrm dt=\int_0^{\pi/3}\frac{\tan^2t}{\sec t}\,\mathrm dt$

We can write

$\dfrac{\tan^2t}{\sec t}=\dfrac{\frac{\sin^2t}{\cos^2t}}{\frac1{\cos t}}=\dfrac{\sin^2t}{\cos t}=\dfrac{1-\cos^2t}{\cos t}=\sec t-\cos t$

so the integral becomes

$\displaystyle\int_0^{\pi/3}(\sec t-\cos t)\,\mathrm dt=\boxed{\ln(2+\sqrt3)-\frac{\sqrt3}2}$

7 0

3 years ago

Solve the system of equations using the elimination method. 1.Solve {x + 3y = -15

shutvik [7]

An equation is formed of two equal expressions. The solution is (-9,-2).

<h3>What is an equation?</h3>

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

Given the equation x + 3y = -15 and -3x + 2y = 23,

Step 1- Multiply the equations to make the coefficients match in either the x- or y-variable.

x + 3y = -15

3x + 9y = -45

Step2- After you multiply, add or subtract the two equations.

3x + 9y -3x + 2y = -45 + 23

Step 3- Then solve for the variables that is left.

11y = -22

y = -2

Step4- Substitute the value of y in any one of equations to solve for x.

x + 3(-2) = -15

x - 6 = -15

x = -9

Hence, The solution is (-9,-2).

Learn more about Equation:

brainly.com/question/2263981

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5 0

1 year ago