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Phantasy [73]
3 years ago
11

Complete the table using the relationship between s and c.

Mathematics
1 answer:
Nataly_w [17]3 years ago
7 0

Answer:

s c

2-6

4-12

6-18

8-24

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When a principal amount, P, is invested at an annual interest rate, r, and compounded n times per
GaryK [48]

Answer:

n =2

Step-by-step explanation:

Compound interest:

The compound interest formula is given by:

A(t) = P(1 + \frac{r}{n})^{nt}

Where A(t) is the amount of money after t years, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per year and t is the time in years for which the money is invested or borrowed.

In this question:

The money is compounded every 6 months.

n is the number of times that interest is compounded per year.

Each 6 months means 12/6 = twice a year. So n =2..

8 0
3 years ago
Can someone help me?
soldier1979 [14.2K]

Answer:

Step-by-step explanation:

First your going to plug in what p and q are into the equation so 3(2)^5+10(-3)^2 over 7(2)+1.

Your going to first do (2)^5 and (-3)^2 so it’s going to be 3(32)+10(9) over (multiply the 7(2) first) 14+1.

3(32)+10(9) over 14+1 now multiply 3(32) and 10(9) you should get (96)+(90) over 15.

add 96+90 to get 186 over 15.

then divide how many times 15 can go into 186 you should get 12 6/15 and divide 6/15 by 3 to get your final answer 12 2/5.

I hope this helps!

5 0
3 years ago
Cameron's book log shoes he reads total of 4\1/4 hours last month how many minutes is that
Romashka-Z-Leto [24]
260 minutes. 4 times 60 = 240 + 20 minutes i s the quarter
8 0
3 years ago
Read 2 more answers
A rectangular kitchen is 11 ft by 17 ft. How many square tiles, each with a perimeter 24 inches, are needed to cover the floor?
Alenkasestr [34]

Answer:

7.7916

Step-by-step explanation:

Multiply 11 by 17 which equals 187,

do 187 / 24 which equals 7.7916 tiles.

Hope this helps!

8 0
3 years ago
Find the partial fraction decomposition of the rational expression with prime quadratic factors in the denominator
SpyIntel [72]
\dfrac{5x^4-7x^3-12x^2+6x+21}{(x-3)(x^2-2)^2}=\dfrac{a_1}{x-3}+\dfrac{a_2x+a_3}{x^2-2}+\dfrac{a_4x+a_5}{(x^2-2)^2}
\implies 5x^4-7x^3-12x^2+6x+21=a_1(x^2-2)^2+(a_2x+a_3)(x-3)(x^2-2)+(a_4x+a_5)(x-3)

When x=3, you're left with

147=49a_1\implies a_1=\dfrac{147}{49}=3

When x=\sqrt2 or x=-\sqrt2, you're left with

\begin{cases}17-8\sqrt2=(\sqrt2a_4+a_5)(\sqrt2-3)&\text{for }x=\sqrt2\\17+8\sqrt2=(-\sqrt2a_4+a_5)(-\sqrt2-3)\end{cases}\implies\begin{cases}-5+\sqrt2=\sqrt2a_4+a_5\\-5-\sqrt2=-\sqrt2a_4+a_5\end{cases}

Adding the two equations together gives -10=2a_5, or a_5=-5. Subtracting them gives 2\sqrt2=2\sqrt2a_4, a_4=1.

Now, you have

5x^4-7x^3-12x^2+6x+21=3(x^2-2)^2+(a_2x+a_3)(x-3)(x^2-2)+(x-5)(x-3)
5x^4-7x^3-12x^2+6x+21=3x^4-11x^2-8x+27+(a_2x+a_3)(x-3)(x^2-2)
2x^4-7x^3-x^2+14x-6=(a_2x+a_3)(x-3)(x^2-2)

By just examining the leading and lagging (first and last) terms that would be obtained by expanding the right side, and matching these with the terms on the left side, you would see that a_2x^4=2x^4 and a_3(-3)(-2)=6a_3=-6. These alone tell you that you must have a_2=2 and a_3=-1.

So the partial fraction decomposition is

\dfrac3{x-3}+\dfrac{2x-1}{x^2-2}+\dfrac{x-5}{(x^2-2)^2}
7 0
3 years ago
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