Answer:
B
Step-by-step explanation:
this equation is in the form of ax^2+bx+c
so a is 4, b is -9, and c is 8
The expected value of the first game is -$0.50 and of the second game is -$0.52.
There are 10³ possible numbers for the lottery, and only 1 of them will match in the correct order; this gives a probability of 1/1000. To find the expected value, we multiply this by the winnings (499 after the $1 cost); we also multiply the probability of losing (999/1000) by the amount lost (-1):
1/1000(499)+999/1000(-1)
499/1000 - 999/1000 = -500/1000 = -0.50
For the second game, since the number is "boxed", there are 3! ways to get the correct digits; this gives a probability of 6/1000. Multiply this by the winnings, 79 (after the $1 cost); multiply the probability of losing (994/1000) by the loss (-1):
6/1000(79) + 994/1000(-1) = 474/1000 - 994/1000 = -520/1000= -0.52
Given:
Total amount invested = $9,000
interest rates = 4% and 6%
Let x be the part of 9,000.
Note that annual return on each investment is the same.
0.04x = 0.06(9,000 - x)
0.04x = 540 - 0.06x
0.04x + 0.06x = 540
0.10x = 540
x = 540/0.10
x = 5,400
0.04x = 0.06(9,000 - x)
0.04(5,400) = 0.06(9,000 - 5,400)
216 = 0.06(3,600)
216 = 216
total interest for the year : 216 + 216 = 432
Interest = pricipal * interest rate * term
432 = 9,000 * interest rate * 1 yr
432/9,000 = interest rate
0.048 = interest rate
Interest rate would be 4.8% to get the same interest from the whole 9,000.
I don’t know exactly what you mean but
24 12 times is 288
24/12 is 2
hope this somewhat helps