What is 130.45 + 3.287 ?

The minute hand of a clock is 1.4 centimeters long. How far does the tip of the minute hand travel in 40 minutes? (Round your an

ozzi

Answer:

2.93cm

Step-by-step explanation:

I have to admit, this stumped me but I got o work and here's what I have for you. Hope this helps. TIP: remember it is the minute hand not any other hand.

For this one you will have to find the circumference of the clock because as the min hand goes round and round, it will act as a radius and it will go in a circular motion.

Formula will be π2r= 3.l4 * 2 * 1.4cm=8.792cm per every one revolution of the minute hand. Remembering that for the minute hand to revolve round the clock it has to cover 1 hr = 60min. For you to get the total circumference,

you'll have to take 8.792cm but since it is per every one revolution of the minute hand, multiply it by 40/60min. The answer will be 2.93066cm before rounding off. After rounding off you will have 2.93cm. Quite lengthy but I assure you after practicing you'll have at your fingertips.

3 0

3 years ago

What is the value of x in this triangle?

Sedaia [141]

Since it's a right triangle, we can use SOH-CAH-TOA. So tan(x) = opposite/adjacent = 5/20
tan(x) = 1/4 = 0.25
x = arc-tan (0.25) = 14.04°

8 0

3 years ago

A survey is conducted to find out whether people in metropolitan areas obtain their news from television (Event T), an newspaper

MrMuchimi

Answer:

e) P ( R' | T ) = 0.62857

f) P ( T' | N ) = 0.32258

g) P ( R' | N ) = 0.70968

h) P ( T' | N&R ) = 5/6

Step-by-step explanation:

Given:

- The probability of Television as news source P ( T ) = 0.7

- The probability of Newspaper as news source P ( N ) = 0.62

- The probability of Radio as news source P ( R ) = 0.46

- The probability of Television & Newspaper as news source P (T&N) = 0.42

- The probability of Television & Radio as news source P (T&R) = 0.26

- The probability of Radio & Newspaper as news source P (R&N) = 0.18

- The probability of all 3 as news source P ( T & R & N ) = 0.03

Find:

Given that TV is a news source, what is the probability that radio is not a news source?

Given that newspaper is a news source, what is the probability that TV is not a news source?

Given that newspaper is a news source, what is the probability that radio is not a news source?

Given that both newspaper and radio are news sources, what is the probability that TV is not a news source?

Solution:

- We will first compute the individual probability of each event occurring alone.

P (Television is the only news source) = P(T) - P(T&R) - P(T&N) + P(T&N&R)

P ( Only Television ) = P ( only T ) = 0.7 - 0.42 - 0.26 + 0.03 = 0.05

P (Newspaper is the only news source) = P(N)-P(N&R)-P(T&N)+P(T&N&R)

P ( Only Newspaper ) = P ( only N ) = 0.62 - 0.18 - 0.42 + 0.03 = 0.05

P (Radio is the only news source) = P(R) - P(T&R) - P(N&R) + P(T&N&R)

P ( Only Radio ) = P ( only R ) = 0.46 - 0.26 - 0.18 + 0.03 = 0.05

- Now for part e)

We are asked for a conditional probability of the form as follows:

P ( R' | T ) = P ( R' & T ) / P ( T )

First compute the probability that next news source is not Radio provided it is already a source of TV.

P ( R' & T ) = P( only T ) + P ( only T & N ) = 0.05 + 0.42 - 0.03 = 0.44

Hence,

P ( R' | T ) = 0.44 / 0.7

P ( R' | T ) = 0.62857

- Now for part f)

We are asked for a conditional probability of the form as follows:

P ( T' | N ) = P ( T' & N ) / P ( N )

First compute the probability that next news source is not TV provided it is already a source of Newspaper.

P ( T' & N ) = P( only N ) + P ( only R & N ) = 0.05 + 0.18 - 0.03 = 0.2

Hence,

P ( T' | N ) = 0.2 / 0.62

P ( T' | N ) = 0.32258

- Now for part g)

We are asked for a conditional probability of the form as follows:

P ( R' | N ) = P ( R' & N ) / P ( N )

First compute the probability that next news source is not Radio provided it is already a source of Newspaper.

P ( R' & N ) = P( only N ) + P ( only T & N ) = 0.05 + 0.42 - 0.03 = 0.44

Hence,

P ( R' | N ) = 0.44 / 0.62

P ( R' | N ) = 0.70968

- Now for part h)

We are asked for a conditional probability of the form as follows:

P ( T' | N&R ) = P ( T' & N & R) / P ( N & R )

First compute the probability that next news source is not TV provided it is already a source of both radio and Newspaper.

P ( T' & N & R) = P ( only N & R ) = 0.18 - 0.03 = 0.15

Hence,

P ( T' | N&R ) = 0.15 / 0.18

P ( T' | N&R ) = 5/6

6 0

3 years ago

Team A and Team B play in a competition.

Anuta_ua [19.1K]

Team A: 15 points
Team B: 3 points

Team A has twelve more points than Team B:
A = B + 12
Team A has five times as many points as Team B:
A = B × 5
A = 5B

substitute "A" with "B + 12" to solve for B:
A = 5B
(B + 12) = 5B
B + 12 = 5B
12 = 5B - B
12 = 4B
3 = B
Team B has 3 points
now substitute "B" with 3 to solve for A:
A = 5B
A = 5(3)
A = 15
Team A has 15 points

Check your answer by inputting both values into either equation:
A = 5B
(15) = 5(3)
15 = 15 ✔

A = B + 12
(15) = (3) + 12
15 = 15 ✔

8 0

3 years ago

Read 2 more answers

Jackie scored 81 and 87 on her first two quizzes . Write and solve a compound inequality to find the possible values for a third

asambeis [7]

Answer:

The third score must be larger than or equal to 72, and smaller than or equal 87

Step-by-step explanation:

Let's name "x" the third quiz score for which we need to find the values to get the desired average.

Recalling that average grade for three quizzes is the addition of the values on each, divided by the number of quizzes (3), we have the following expression for the average:

$average=\frac{81+87+x}{3}$

SInce we want this average to be in between 80 and 85, we write the following double inequality using the symbols that include equal sign since we are requested the average to be between 80 and 85 inclusive:

$80\leq average\leq 85\\80\leq \frac{81+87+x}{3} \leq 85\\80\leq \frac{168+x}{3} \leq 85$

Now we can proceed to solve for the unknown "x" treating each inaquality at a time:

$80\leq \frac{168+x}{3}\\3*80\leq 168+x\\240\leq 168+x\\240-168\leq x\\72\leq x$

This inequality tells us that the score in the third quiz must be larger than or equal to 72.

Now we study the second inequality to find the other restriction on "x":

$\frac{168+x}{3} \leq 85\\168+x\leq 85 *3\\168+x\leq 255\\x\leq 255-168\\x\leq 87$

This ine $72\leq x} \leq 87$ quality tells us that the score in the third test must be smaller than or equal to 87 to reach the goal.

Therefore to obtained the requested condition for the average, the third score must be larger than or equal to 72, and smaller than or equal 87:

4 0

3 years ago

What is 130.45 + 3.287 ?​

What is 130.45 + 3.287 ?