Answer:
one point (on origin),
Step-by-step explanation:
graph of Y=X^2 is parabolic ,and x intecept means the point where ,Y COORDINATE (ORDINATE) becomes 0
so now after putting y=0 in eqution we got
x^2=0
i.e, x=0
that means at (0,0) ,so only one point!
✌️:)
Answer:
30° = m∠GFH
Step-by-step explanation:
Since ∠EFH and ∠GFH are complementary, the sum of their measures i 90.
Let x = m∠GFH
2x = m∠EFH
m∠GFH + m∠EFH = 90
x + 2x = 90
3x = 90
x = 30° = m∠GFH
(x+2)(x+8)(x+k)=x^3+9x^2+6x-16
(x^2+10x+16)(x+k)=x^3+9x^2+6x-16
x^3+10x^2+16x+kx^2+10kx+16k=x^3+9x^2+6x-16
kx^2+10kx+16k=-x^2-10x-16
k(x^2+10x+16)=-x^2-10x-16
k=(-x^2-10x-16)/(x^2+10x+16)
k=-1
so the width is (x-1)
8a^2 + 3a^2
11a^2
since both have a^2 you only have to add the coefficients
Let C be the center of the circle. The measure of arc VSU is 
, so the measure of the minor arc VU is 
. The central angle VCU also has measure 
.
Triangle CUV is isosceles, so the angles CVU and CUV are congruent. The interior angles of any triangle are supplementary (they add to 180 degrees) so
UT is tangent to the circle, so CU is perpendicular to UT. Angles CUV and VUT are complementary, so
So finally,
degrees.
