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Lilit [14]
3 years ago
6

Write an equation of the line that passes

Mathematics
1 answer:
adell [148]3 years ago
8 0

Answer:

y =  \frac{5}{4} x - 5

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Express this to single logarithm
zzz [600]

Answer:  \log_{2}\left(\frac{q^2\sqrt{m}}{n^3}\right)

We have something in the form log(x/y) where x = q^2*sqrt(m) and y = n^3. The log is base 2.

===========================================================

Explanation:

It seems strange how the first two logs you wrote are base 2, but the third one is not. I'll assume that you meant to say it's also base 2. Because base 2 is fundamental to computing, logs of this nature are often referred to as binary logarithms.

I'm going to use these three log rules, which apply to any base.

  1. log(A) + log(B) = log(A*B)
  2. log(A) - log(B) = log(A/B)
  3. B*log(A) = log(A^B)

From there, we can then say the following:

\frac{1}{2}\log_{2}\left(m\right)-3\log_{2}\left(n\right)+2\log_{2}\left(q\right)\\\\\log_{2}\left(m^{1/2}\right)-\log_{2}\left(n^3\right)+\log_{2}\left(q^2\right) \ \text{ .... use log rule 3}\\\\\log_{2}\left(\sqrt{m}\right)+\log_{2}\left(q^2\right)-\log_{2}\left(n^3\right)\\\\\log_{2}\left(\sqrt{m}*q^2\right)-\log_{2}\left(n^3\right) \ \text{ .... use log rule 1}\\\\\log_{2}\left(\frac{q^2\sqrt{m}}{n^3}\right) \ \text{ .... use log rule 2}

8 0
3 years ago
Which polynomial is in standard form?
miv72 [106K]

Answer:

(C) 19x+6^2+2

Step-by-step explanation:

8 0
3 years ago
The ratio of powder to water is 1:8 if there are 32 cups of powder how many cups of water are needed
In-s [12.5K]
There are 256 cups of water needed. I hope this helped.
6 0
3 years ago
Can someone help me out please
sveticcg [70]
Mucopolysaccharidosis
3 0
2 years ago
What is the answer for 7.5+2.3y-y
Alexxx [7]

Answer:

9.8

Step-by-step explanation:

7.5+2.3y-y

Subtract y

7.5+2.3

Then Add

9.8

7 0
3 years ago
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