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alex41 [277]
3 years ago
9

Help with these two questions? (also yall like my diluc homescreen)

Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
6 0
1. GCF is 7 so answer is 7(5+6)

2. GCF is 5 so answer is 5(3+8)
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John’s friend told him that he could earn $49 for handing out flyers at a local concert John wants to calculate the hourly rate
son4ous [18]

\frac{3.5x}{3.5}  =  \frac{49}{3.5}
x = 14
5 0
3 years ago
When you subtract one negative integer from another, will your answer be greater than or less than the integer you started with?
SVEN [57.7K]
So say for example u have -7 - (-5), think of subtracting integers as adding the opposite, so ur adding the opposite of -5, the opposite of -5 is 5, so ur adding -7 and 5= -2
another one: -15 - (-18)
again, adding the opposite. -15 plus positive 18= 3

8 0
3 years ago
Question 11 (2.5 points)
Rama09 [41]

Answer:

D

Step-by-step explanation:

The answer is d, because a represents adults, and c represent children. It's $45 per adult, so $45a, and $30 per child, so $30c. a+c is equal to 10, because that's how many tickets were purchased. $45a+$30c=345, because $345 is the total amount spent on tickets.

3 0
3 years ago
If there are 52 cards in a deck with four suits (hearts, clubs, diamonds, and spades), how many ways can you select 5 diamonds a
Luba_88 [7]

Answer:

12C5 *(12C3) = 792*220 =174240 ways

Step-by-step explanation:

For this case we know that we have 12 cards of each denomination (hearts, diamonds, clubs and spades) because 12*4= 52

First let's find the number of ways in order to select 5 diamonds. We can use the combinatory formula since the order for this case no matter. The general formula for combinatory is given by:

nCx = \frac{n!}{x! (n-x)!}

So then 12 C5 would be equal to:

12C5 = \frac{12!}{5! (12-5)!}=\frac{12!}{5! 7!} = \frac{12*11*10*9*8*7!}{5! 7!}= \frac{12*11*10*9*8}{5*4*3*2*1}=792

So we have 792 was in order to select 5 diamonds from the total of 12

Now in order to select 3 clubs from the total of 12 we have the following number of ways:

12C3 = \frac{12!}{3! 9!}=\frac{12*11*10*9!}{3! 9!} =\frac{12*11*10}{3*2*1}=220

So then the numbers of ways in order to select 5 diamonds and 3 clubs are:

(12C5)*(12C3) = 792*220 =174240 ways

3 0
3 years ago
1 kg = ___ g<br><br> A : 1<br> B : 10<br> C : 100<br> D : 1,000
zlopas [31]
D: 1000 grams

thats the answer
7 0
3 years ago
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