Help with these two questions? (also yall like my diluc homescreen)

QUALITY CONTROL1)Specifications for a part for a DVD player state that the part should weigh between 24.6 and 25.6 ounces. The p

Phantasy [73]

Answer:

Step-by-step explanation:

Given that,

μ = 25.1

σ = 0.26

a) since standard deviation is ideal measure of dispersion , a combination of control chart for mean x and standard deviation known as

$\bar x \\\text {and}\\\mu$

Chart is more appropriate than $\bar x$ and R - chart for controlling process average and variability

so we use

$\bar x \\\text {and}\\\mu$ charts

b)

n = 11

we have use 2 σ confidence

so, control unit for $\bar x$ chart are

upper control limit = $\mu +2\times\frac{ \sigma}{\sqrt{n} }$

lower control limit = $\mu -2\times\frac{ \sigma}{\sqrt{n} }$

control limit = μ

μ = 25.1

upper control limit =

$25.1+2\times \frac{0.26}{\sqrt{11} } \\\\=25.2567$

lower control limit =

$25.1-2\times \frac{0.26}{\sqrt{11} } \\\\=24.9432$

Upper control limit and lower control limit are in between the specification limits , that is in between 24.9 and 25.6

so, process is in control

c) if we use 3 sigma limit with n = 11

then

upper control limit = $\mu +3\times\frac{ \sigma}{\sqrt{n} }$

$25.1+3\times\frac{0.26}{\sqrt{11} } \\\\=25.3351$

lower control limit = $\mu -2\times\frac{ \sigma}{\sqrt{n} }$

$25.1-3\times\frac{0.26}{\sqrt{11} } \\\\=24.8648$

control limit is 25.1

Then, process is in control since upper control limit and lower control limit lies between specification limit

So, process is in control

7 0

2 years ago

2а + 20 = -3а - 5 pls help

sammy [17]

Answer: A= -5

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Please help Im so confused!

mars1129 [50]

His mistake was adding 12+2 when he was supposed to subtract.

8 0

2 years ago

Now, you will consider Option 1, setting a maximum shower time of 10 minutes.

matrenka [14]

The maximum shower time is an illustration of mean and median, and the conclusion is to disagree with Blake's claim

<h3>How to interpret the shower time?</h3>

The question is incomplete, as the dataset (and the data elements) are not given.

So, I will answer this question using the following (assumed) dataset:

Shower time (in minutes): 6, 7, 7, 8, 8, 9, 9, 9, 12, 12, 12, 13, 15,

Calculate the mean:

Mean = Sum/Count

So, we have:

Mean = (6+ 7+ 7+ 8+ 8+ 9+ 9+ 9+ 12+ 12+ 12+ 13+ 15)/13

Mean = 9.8

The median is the middle element.

So, we have:

Median = 9

From the question, we have the following assumptions:

The shower time of students whose shower times are above 10 minutes, is 10 minutes
Other shower time remains unchanged.

So, the dataset becomes: 6, 7, 7, 8, 8, 9, 9, 9, 10, 10, 10, 10, 10

The mean is:

Mean = (6+ 7+ 7+ 8+ 8+ 9+ 9+ 9+ 10+ 10+ 10+ 10+ 10)/13

Mean = 8.7

The median is the middle element.

So, we have:

Median = 9

From the above computation, we have the following table:

Initial Final

Mean 9.8 8.7

Median 9 9

Notice that the mean value changed, but it did not go below 8 as claimed by Blake; while the median remains unchanged.

Hence, the conclusion is to disagree with Blake's claim