8 is the largest possible value of the median of all nine numbers in this list.
Lets simplify it,
⇒ The given six numbers are 7,8,3,5,9 and 5.
⇒ Arrange the six numbers in order 3,5,5,7,8,9.
⇒ We have three more numbers to insert into the list, and the median will be the highest 5(and 5 lowest) number on the list. If the three numbers are greater than 9, the median will be the highest it can possible be.
∴ The median is the 5th item of data which is 8.
∴ Median=8
Hence 8 is the largest possible value of the median of all nine numbers in this list.
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The answer is 30. you can find the unit rate but the calculator was invented a long time ago so i used that ;)
Answer:
Step-by-step explanation:
Given
Required
Use the expression to prove a trigonometry identity
The given expression is not complete until it is written as:
Going by the Pythagoras theorem, we can assume the following.
- a = Opposite
- b = Adjacent
- r = Hypothenuse
So, we have:
Having said that:
The expression can be further simplified as:
Substitute values for sin and cos
becomes
An= A1 r ^(n-1)
An= -4 (-3)^(n-1)
An= -4 (-3)^(7-1)
An= -4 (729)
An= -2916
I think this is right :)
Answer:
A
Step-by-step explanation:
