Question

Help please! First answer and correct gets brainlist!

Answer 1

Answer:

Dolores is incorrect

Step-by-step explanation:

the surface area of the 1 ticket zone is ($\pi 9^{2}$)-($\pi 6^{2}$) which is ≈ 141 in ^3

the surface area of the 2 tickest zone is ($\pi 6^{2}$)-($\pi 1^{2}$) which is ≈ 110 in^3

141>110

the surface area of the 1 ticket zone is larger than the area of the two ticket zone so its not equal, so the one ticket zone has the highest probability

Answer 2

Answer:

just adding this answer so you can give the other person brainliest :)

Step-by-step explanation: