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Goryan [66]
3 years ago
5

What expression are equivalent to 8(-10x+3.5y-7)

Mathematics
1 answer:
torisob [31]3 years ago
7 0

Answer: -80x+28y-56

kinda late 8( sorry

Step-by-step explanation:

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A number x increased by 4 is less than -18
Bond [772]

x + 4 < -18

x < -18 - 4

x < -22

x is less than -22

5 0
3 years ago
To the nearest whole degree, what angle measure has a tangent of 2.0874?
kotykmax [81]
To find an angle measure, you would do inverse tan.

{ \tan }^{ - 1} (2.0874)
You may need to hit the second button on your calculator to get this function.

Your answer turns up to be 64.402~~~~.

Rounded, the answer is 64 degrees.

Hope this helps!

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3 0
4 years ago
6(2x+1)+5=13-2 +4x+8x
nexus9112 [7]
This Equation is true because both sides are equal
5 0
3 years ago
The half-life of Carbon 14 (C-14) is 5230 years. Determine the decay-rate pa-rameterλfor C-14.
Lady bird [3.3K]

Answer:

λ = 1.3252 x 10⁻⁴

Step-by-step explanation:

Since we are already given the half-life, the decay expression can be simplified as:

N(t) = N_0*e^{-\lambda t}\\\frac{N(half-life)}{N_0}=0.5

For a half-life of t =5230 years:

0.5 = e^{(-\lambda t)} \\ln(0.5) = -\lambda * 5230\\\lambda = 1.3252*10^{-4}

The decay-rate parameter λ for C-14 is 1.3252 x 10⁻⁴

7 0
3 years ago
A circular cylindrical container, open at the top, and having a capacity of 24pi cubic inches, is to be manufactured. If the cos
otez555 [7]

Answer: radius r = 2 inches

height h = 6 inches

Step-by-step explanation:

Given;

Volume V = 24πin3

Volume of a cylinder is given by

V = πr^2h

h = V/πr^2. ....1

Where, h = height and r = radius of cylinder

For the surface area of the cylinder with open top. we have,

S = 2πrh + πr^2

For the cost of materials used, let k represent the cost of materials used for the body of the cylinder.

Then, for the bottom will be 3k

Total cost will be represented by C, which gives

C = 2πrhk + 3πr^2k. .....2

Substituting eqn 1 to 2, we have;

C = 2πrVk/πr^2 + 3πr^2k

C = 2Vk/r + 3πr^2k

The material cost is minimum at dC/dr = 0

dC/dr = -2Vk/r^2 + 6πrk =0

6πrk = 2Vk/r^2

r^3 = 2V/6π

r = (2×24π/6π)^-3

r = (8)^-3

r = 2

Substituting r = 2 into eqn1

h = 24π/π(2^2)

h = 24/4 = 6

h = 6

5 0
4 years ago
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