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Setler79 [48]
3 years ago
5

PLS IT FOR MY ECONOMICS CLASS

Mathematics
1 answer:
Zanzabum3 years ago
7 0

Answer:

  • 7. Hourly wage: 10 hr
  • 2, 20 : 4, 40: 6, 60: 8, 80: 10, 100: 12, 120: 14, 140: 16, 160: 18, 180: 20, 200
  • It should just be a negative slope
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Find the quotient of 213.21 and 15.8. Round your answer to the nearest tenth.
gladu [14]
213.21 divided by 15.8 is 13.494 which would be rounded to 13.5
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3 years ago
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Solve system of linear equation with substitution
Blizzard [7]

Answer:

x=1, y=2

Step-by-step explanation:

solve by substitution so substitute x= 6y-11 in the next equation

3 (6y-11) - 2y = -1

18y -33-2y = -1

16y = 33-1

y= 32/16 =2

x= 6y -11 = 6*2 -11 = 12 -11 = 1

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3 years ago
0.03858 *0.02 leaving your answer I’m a standard form
djyliett [7]

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0.0007716

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8 0
3 years ago
Please help me solve this! I’ve been stuck for ages! Thankyou
castortr0y [4]

90cm on of the each f and g

8 0
3 years ago
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Help please I need 5 points total. i need 2 to left of vertex. i need vertex. i need 2 to right of vertex. Please, quickly, I am
zlopas [31]

We are given with a quadratic equation which represents a Parabola , we need to find the vertex of the parabola , But let's recall that , For any quadratic equation of the form ax² + bx + c = 0 , the vertex of the parabola is given by ;

{\quad \qquad \boxed{\bf{Vertex = \left(\dfrac{-b}{2a},\dfrac{-D}{4a}\right)}}}

Where , D = b² - 4ac (Discriminant)

Now , On comparing the given equation with ax² + bx + c , we have

⇢⇢⇢ <em><u>a = 1 , b = - 10 , c = 2</u></em><em><u>7</u></em>

Now , Calculating D ;

{:\implies \quad \sf D=(-10)^{2}-4\times 1\times 27}

{:\implies \quad \sf D=100-108}

{:\implies \quad \bf \therefore \quad D=-8}

Now , Calculating the vertex ;

{:\implies \quad \sf Vertex =\bigg\{\dfrac{-(-10)}{2\times 1},\dfrac{-(-8)}{4\times 1}\bigg\}}

{:\implies \quad \sf Vertex = \left(\dfrac{10}{2},\dfrac{8}{2}\right)}

{:\implies \quad \bf \therefore \quad Vertex = (5,2)}

Hence , The vertex of the parabola is at (5,2)

Note :- As the Discriminant < 0 . So , the equation will have imaginary roots .

Refer to the attachment for the graph as well .

5 0
3 years ago
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